- #1
smellsey
- 2
- 0
Homework Statement
You have 10 m of 0.55 mm diameter copper wire and a battery capable of passing 13 A through the wire. What magnetic field strength could you obtain inside a 2.8 cm diameter solenoid wound with the wire as closely spaced as possible?
Homework Equations
Turns of a solenoid = length of wire/ (2[tex]\pi[/tex] * radius of solenoid)
B = ( [tex]\mu[/tex]*turns of a solenoid * Current)/([tex]\sqrt{}(4(radius of solenoid)^2+(radius of copper wire)^2[/tex] where [tex]\mu = 4\pi *10^-7[/tex]
I believe that's right once you do the integration
The Attempt at a Solution
I tried to solve this and I got B = 0.27 T but it isn't right! I've tried over and over again, but I can't see to get the right answer.
Thanks!