- #1
Kathi201
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A figure has a 3.0T magnetic field that is normal to the plane of a conducting, circular loop with a resistance of 1.5 ohms and a radius of .024m. The magnetic field is directed out of the paper. The area of the non-circular portion of the wire is considered negligible compared to that of the circular loop.
a. What is the magnitude of the average induced emf in the loop if the magnitude of the magnetic field is doubled in .4s
b. What is the average current around the loop if the magnitude of the magnetic field is doubled in .4s
c. If the magnetic field is held constant at 3.0T and the loop is pulled out of the region that contains the field in .2s, what is the magnitude of the average induced emf in the loop?
d. If the magnetic field is held constant at 3.0T and the loops is pulled out of the region that contains the field in .2s, at what rate is energy dissipated in R?
For a. I thought to use the equation E = Q/T and since Q=BCos(angle)A I found the answer to be .027V
Then on B I got stuck. I am using the equation E = L (I/T), therefore I = Et / L but I am getting the wrong answer. I think I might be using the wrong equation.
For C I used the equation E = N (Q/T) and Q = BA = 3.0T x (3.14 x .024^2) = .0054 and if you divide that by .2s I got the answer for C to be 2.7 x 10^-2 V
Then on D I am stuck again. I am using the equation P = (B^2 x V^2 x L^2) / 1.5 ohms = 2.8 x 10^-7, however this is not one of my answer choices so I am also doing this problem wrong.
If I could get any help on b and d I would really appreciate it!
a. What is the magnitude of the average induced emf in the loop if the magnitude of the magnetic field is doubled in .4s
b. What is the average current around the loop if the magnitude of the magnetic field is doubled in .4s
c. If the magnetic field is held constant at 3.0T and the loop is pulled out of the region that contains the field in .2s, what is the magnitude of the average induced emf in the loop?
d. If the magnetic field is held constant at 3.0T and the loops is pulled out of the region that contains the field in .2s, at what rate is energy dissipated in R?
For a. I thought to use the equation E = Q/T and since Q=BCos(angle)A I found the answer to be .027V
Then on B I got stuck. I am using the equation E = L (I/T), therefore I = Et / L but I am getting the wrong answer. I think I might be using the wrong equation.
For C I used the equation E = N (Q/T) and Q = BA = 3.0T x (3.14 x .024^2) = .0054 and if you divide that by .2s I got the answer for C to be 2.7 x 10^-2 V
Then on D I am stuck again. I am using the equation P = (B^2 x V^2 x L^2) / 1.5 ohms = 2.8 x 10^-7, however this is not one of my answer choices so I am also doing this problem wrong.
If I could get any help on b and d I would really appreciate it!