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Hi guys! This is related to a recent thread but since that thread became cluttered, I figured it would be more coherent to just ask the question here. Say we have a congruence of charged dust particles in some space-time with tangent field ##\xi^a##. The energy-momentum of the charged dust is given by ##T^{\text{charges}}_{ab} = \rho \xi_a \xi_b## where as usual ##\rho## is the mass density as measured by observers comoving with the dust. The charge density ##\sigma## is also as measured by comoving observers hence the 4-current ##j^a = \sigma \xi^a## because in a frame field comoving with the dust the 4-current will only have a time-like component (which will be the charge density). However there is an additional energy-momentum from the electromagnetic field carried by the charged dust particles and this is given by ##T^{\text{EM}}_{ab} = F_{ac}F_{b}{}{}^{c} - \frac{1}{4}g_{ab}F^{cd}F_{cd}##.
Now ##\nabla^a T^{\text{charges}}_{ab}, \nabla^aT^{\text{EM}}_{ab}\neq 0## by themselves. I've seen authors prove that ##\nabla^a T_{ab} = \nabla^a( T^{\text{charges}}_{ab}+ T^{\text{EM}}_{ab}) = 0## by assuming that (1) the individual charged fluid elements satisfy the Lorentz force law, which can be written as ##\rho \xi^b\nabla_b \xi^a = \sigma F^{ab}\xi_b## for the congruence itself and that (2) the dust satisfy conservation of mass current ##\nabla_a (\rho \xi^a) = 0##.
Usually, if we have charge free dust (so that ##T_{ab} = \rho \xi_a \xi_b## is the only energy-momentum source), one first assumes that ##\nabla ^a T_{ab} = 0## and then derives the mass current conservation for the dust from this. Here, in the presence of both the energy-momentum of the dust and the energy-momentum of the electromagnetic fields they carry, these authors are trying to show that ##\nabla^a T_{ab} = 0## for the total energy-momentum ##T_{ab}##, and to do this they first assume that mass current conservation holds. Why can we assume it holds, before even showing that ##\nabla^a T_{ab} = 0##?
Thanks in advance!
EDIT: Ok nevermind, I overlooked a very simple thing. Well that's that :)!
Now ##\nabla^a T^{\text{charges}}_{ab}, \nabla^aT^{\text{EM}}_{ab}\neq 0## by themselves. I've seen authors prove that ##\nabla^a T_{ab} = \nabla^a( T^{\text{charges}}_{ab}+ T^{\text{EM}}_{ab}) = 0## by assuming that (1) the individual charged fluid elements satisfy the Lorentz force law, which can be written as ##\rho \xi^b\nabla_b \xi^a = \sigma F^{ab}\xi_b## for the congruence itself and that (2) the dust satisfy conservation of mass current ##\nabla_a (\rho \xi^a) = 0##.
Usually, if we have charge free dust (so that ##T_{ab} = \rho \xi_a \xi_b## is the only energy-momentum source), one first assumes that ##\nabla ^a T_{ab} = 0## and then derives the mass current conservation for the dust from this. Here, in the presence of both the energy-momentum of the dust and the energy-momentum of the electromagnetic fields they carry, these authors are trying to show that ##\nabla^a T_{ab} = 0## for the total energy-momentum ##T_{ab}##, and to do this they first assume that mass current conservation holds. Why can we assume it holds, before even showing that ##\nabla^a T_{ab} = 0##?
Thanks in advance!
EDIT: Ok nevermind, I overlooked a very simple thing. Well that's that :)!
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