MHB Mechanics- connected particles

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Two smooth pulleys are positioned 8m apart with a light inextensible rope and three boxes, each hanging at the same horizontal level. The total length of the rope is confirmed to be 16m, leading to a calculation for the mass m of the middle box. Initial calculations suggested m = 7.5 kg, but the correct answer is 6 kg, as verified through solving a radical equation. The method involves setting up the equation h + √(h² + 16) = 8 and solving for h, which leads to the correct mass. The discussion emphasizes the importance of understanding radical equations for solving similar problems.
Shah 72
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Two smooth pulleys are 8m apart at the same horizontal level. A light inextensible rope passes over the pulleys and a box of mass 5kg hangs at each end of the rope. A third box of mass m kg is attached to the midpoint of the rope and hangs between the pulleys so that all the three boxes are at the same horizontal
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level. The total length of the box is 16m. Find the value of m
 
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total length of the box? … maybe the string length is 16 m ?

if so, I get m = 7.5 kg
 
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skeeter said:
total length of the box? … maybe the string length is 16 m ?

if so, I get m = 7.5 kg
Iam so so sorry again typo error. Its the total length of the rope = 16m
 
skeeter said:
total length of the box? … maybe the string length is 16 m ?

if so, I get m = 7.5 kg
The ans in the textbook says 6 kg.
 
skeeter said:
total length of the box? … maybe the string length is 16 m ?

if so, I get m = 7.5 kg
Can you pls pls tell me how to work it out?
 
Shah 72 said:
The ans in the textbook says 6 kg.

6 kg is correct … I used the wrong value for a trig ratio.
 
skeeter said:
6 kg is correct … I used the wrong value for a trig ratio.
Can you pls pls tell me the method you worked it out? I have no clue how to solve it.
 
3D285147-A12D-4FFE-868E-957D07107419.jpeg
 
  • #10
$h + \sqrt{h^2+16} = 8$

 
  • #11
skeeter said:
$h + \sqrt{h^2+16} = 8$

By squaring both sides I will get 2h^2=-8 .
 
  • #12
$h + \sqrt{h^2+16} = 8$

$\sqrt{h^2+16} = 8-h$

square both sides …

$h^2+16 = 64 - 16h + h^2$

$16h = 48$

$h =3$

check solution …

$3 + \sqrt{3^2+16} = 3 + 5 = 8$

checks good.

recommend you review solving radical equations …
 
  • #13
skeeter said:
$h + \sqrt{h^2+16} = 8$

$\sqrt{h^2+16} = 8-h$

square both sides …

$h^2+16 = 64 - 16h + h^2$

$16h = 48$

$h =3$

check solution …

$3 + \sqrt{3^2+16} = 3 + 5 = 8$

checks good.

recommend you review solving radical equations …
Thank you so so much! None of these things are explained in the textbook. Iam really struggling with the pulley and string questions. I will surely look into solving radical equations.
 

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