- #1
Ry122
- 565
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200g of steel was placed on a big block of ice.
The ice was 0 degrees C.
The metal was 150 degrees C.
How much ice gets melted?
My attempt:
Q=mc(changeinT)
Q=.2(460)150
Q=13800
Q=ML
13800=M(3.34x10^5)
M=.041317 kg is melted
Is this correct?
The ice was 0 degrees C.
The metal was 150 degrees C.
How much ice gets melted?
My attempt:
Q=mc(changeinT)
Q=.2(460)150
Q=13800
Q=ML
13800=M(3.34x10^5)
M=.041317 kg is melted
Is this correct?