- #1
jean140
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- TL;DR Summary
- I want to know why the choice of a signature (-+++) or (+---) has no physical impact.
Hello,
I've always heard that the choice of signature for the metric was just a matter of convention, i.e. taking (+---) or (-+++) had no physical impact. The groups O(1,3) and O(3,1) being isomorphic it made sense to me.
However, I came across an article discussing the Pin(1,3) and Pin(3,1) non - isomorphic groups . It says, and I quote :
So that would mean that it would be possible experimentally to find the true signature of the metric ? And so it would be wrong to say that the choice of signature is just a matter of convention ?
Thanks.
Edit : the article's link https://arxiv.org/abs/math-ph/0012006
I've always heard that the choice of signature for the metric was just a matter of convention, i.e. taking (+---) or (-+++) had no physical impact. The groups O(1,3) and O(3,1) being isomorphic it made sense to me.
However, I came across an article discussing the Pin(1,3) and Pin(3,1) non - isomorphic groups . It says, and I quote :
Two notable positive results show that the existence of two Pin groups is relevant to physics:
- In a neutrinoless double beta decay, the neutrino emitted and reabsorbed in the course of the interaction can only be described in terms of Pin(3,1).
- If a space is topologically nontrivial, the vacuum expectation values of Fermi currents defined on this space can be totally different when described in terms of Pin(1,3) and Pin(3,1).
So that would mean that it would be possible experimentally to find the true signature of the metric ? And so it would be wrong to say that the choice of signature is just a matter of convention ?
Thanks.
Edit : the article's link https://arxiv.org/abs/math-ph/0012006