- #1
Barchie
- 18
- 0
Homework Statement
For f(x) = |x^2-9|/x-3 and a=3, discuss the limiting behavior of f(x) as x->a+, as x->a- and as x->a
The Attempt at a Solution
Am i right to say that the limit for x-> 3 is undefined? I am also a little confused with the a+ and the a-
for a+ i would say that 3+^2-9/3+-3 = 0+/0+ = 1 and for a- it would = -1 ... but i get the feeling that this is wrong... any guidance?
Homework Statement
For f(x) = |x^2-9|/x-3 and a=3, discuss the limiting behavior of f(x) as x->a+, as x->a- and as x->a
EDIT: ok so putting the values into a calculator give me 6 & -6 i am content with those answers... i am also think i am getting closer with the idea that i can factor the top line into:
(x+3)(x-3) and then cancel the (x-3)'s leaving me with x+3 which would explain 6, but not -6.
can i cancel the denominator with the abs value numerator?
Thanks for your time.
Last edited: