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electricalguy
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I have a transformer with the primary winding connected to a 115 volts 60Hz supply, the current is 0.230 amps AC, with a resistance of 25.3 ohms. The secondary winding is connected to an inductive load. The voltage across the secondary winding when the load is connected is 13.14 voltage AC with 0.2 amps AC.
I calculated the inductance of the primary winding to be Z = 115/0.23 = 500 ohms, xL = √500∧2/25.3∧2 = 499.3594948 ohms,
L=499.3594948/2×π×hz = 499.3594948/376.9911184 = 1.324592213 Henry.
I measured the secondary winding by supplying an AC supply through it and the load inductance in series at the same time using a programmable AC power supply unit and measuring the voltage drop across each with the supply current and performing the same equation as above. I supplied 15 volts AC at 60 Hz and 0.223 amps AC, the secondary winding had a voltage of 2.04 V and the load inductance had 12.87 volts. The resistance of the secondary winding is 0.65 ohms, the resistance of the load is 1.860 ohms. In parallel their resistance is 0.449 ohms.
Using the same math as above I calculated the secondary winding to have an inductance of 0.024204 Henry and the load to have an inductance of 0.153008974 Henry. In parallel I calculated the total inductance of the secondary circuit to be 0.020898509 Henry.
My question is with the circuit running with a supply from the primary winding the math shows the inductance to be Z=13.14/0.2=65.7, xL=√65.7∧2/0.449∧2=65.69846573 ohms,
L=65.69846573/376.9911184=0.174270592 Henry. To me this doesn't seem correct. How can the value of inductance change like that from what I independently measured?
I do understand that the voltage will be the same in a parallel circuit. Can someone please show me where I am going wrong and help to understand this better?
I calculated the inductance of the primary winding to be Z = 115/0.23 = 500 ohms, xL = √500∧2/25.3∧2 = 499.3594948 ohms,
L=499.3594948/2×π×hz = 499.3594948/376.9911184 = 1.324592213 Henry.
I measured the secondary winding by supplying an AC supply through it and the load inductance in series at the same time using a programmable AC power supply unit and measuring the voltage drop across each with the supply current and performing the same equation as above. I supplied 15 volts AC at 60 Hz and 0.223 amps AC, the secondary winding had a voltage of 2.04 V and the load inductance had 12.87 volts. The resistance of the secondary winding is 0.65 ohms, the resistance of the load is 1.860 ohms. In parallel their resistance is 0.449 ohms.
Using the same math as above I calculated the secondary winding to have an inductance of 0.024204 Henry and the load to have an inductance of 0.153008974 Henry. In parallel I calculated the total inductance of the secondary circuit to be 0.020898509 Henry.
My question is with the circuit running with a supply from the primary winding the math shows the inductance to be Z=13.14/0.2=65.7, xL=√65.7∧2/0.449∧2=65.69846573 ohms,
L=65.69846573/376.9911184=0.174270592 Henry. To me this doesn't seem correct. How can the value of inductance change like that from what I independently measured?
I do understand that the voltage will be the same in a parallel circuit. Can someone please show me where I am going wrong and help to understand this better?
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