Normal force between stacked boxes

In summary, the forces from gravity and its normal force cancel out, leaving us with the normal forces from the boxes. The net normal force between the two boxes is 17.5N. When looking at the free body diagram for the top box, the normal force can be calculated using the equation F(normal) = m(g+a) or 24.6N in this case. The acceleration of gravity is 9.8 m/s^2 and the net force acting on the box is 19.6N.
  • #1
jackattack825
4
0
Homework Statement
The UPS person is delivering two rectangular boxes to the 4th floor of a building. The boxes are stacked vertically in the elevator. The one on the bottom has a mass of 5.00 kg and the one on the top has a mass of 2.00 kg. The elevator, the UPS person, and both boxes are accelerating upward at 2.50 m/s^2. What is the magnitude of the normal force between the two boxes?
Relevant Equations
Force(net) = mass * acceleration
Σ F= -F(gravity from earth) + F(normal from earth) -F(normal from top box) +F(normal from bottom box) = (2+5) * 2.5
The forces from gravity and it's normal force cancel out, leaving us with the normal forces from the boxes.

F(net of normal from boxes) = (2+5) * 2.5
= 17.5N
 
Physics news on Phys.org
  • #2
No. You seem to be looking at the system of both boxes, where their combined weight acts down, and the normal force of the elevator on the bottom box acts up. That’s it, the other normal forces are internal and do not enter in your equation. Try looking at a free body diagram of the top box. The problem asks for the normal force between the 2 boxes.
 
  • #3
thanks for the speedy response

the free body diagram for the top box would just be gravity pulling down and a normal force from the other box pushing up, correct?

EDIT: based on that logic, I got F(normal)= m(g+a) or 2(-9.8+2.5)= 14.6N
 
  • #4
jackattack825 said:
thanks for the speedy response

the free body diagram for the top box would just be gravity pulling down and a normal force from the other box pushing up, correct?
Yes
EDIT: based on that logic, I got F(normal)= m(g+a) or 2(-9.8+2.5)= 14.6N
No. The acceleration is given as a, not a + g. Try again, using the net force (the algebraic sum of
both forces ) acting on the box, on the left side of your equation.
 
  • #5
PhanthomJay said:
No. The acceleration is given as a, not a + g. Try again, using the net force (the algebraic sum of
both forces ) acting on the box, on the left side of your equation.

So you are saying:

F(normal) - F(gravity) = ma , F(normal) - 9.8= 2 * 2.5 , F(normal)= 5+9.8= 14.8N
 
  • #6
The acceleration of gravity is 9.8 m/s^2, but you are looking for the force of gravity, not the acceleration of gravity.
 
  • #7
ah i got it now

F(normal) -F(gravity) =ma
F(normal) - 9.8*2 = 2*2.5
F(normal) = 5+19.6 = 24.6N
 
  • #8
Yup!
 

What is the normal force between stacked boxes?

The normal force between stacked boxes is the force that each box exerts on the box above it due to the weight of the boxes and the force of gravity. It is also known as the contact force or support force.

How is the normal force calculated?

The normal force can be calculated by multiplying the mass of the box by the acceleration due to gravity, or by using the formula F=mg, where F is the normal force, m is the mass and g is the acceleration due to gravity.

Does the normal force change if the boxes are on a slope?

Yes, the normal force will change if the boxes are on a slope. In this case, the normal force will be equal to the component of the weight of the box that is perpendicular to the slope.

How does the normal force affect the stability of the stacked boxes?

The normal force plays a crucial role in the stability of stacked boxes. It is responsible for keeping the boxes in place and preventing them from toppling over. The greater the normal force, the more stable the stacked boxes will be.

Can the normal force be greater than the weight of the top box?

Yes, the normal force can be greater than the weight of the top box. This can happen if there is an external force acting on the stacked boxes, such as wind, pushing the boxes together and increasing the normal force between them.

Similar threads

  • Introductory Physics Homework Help
Replies
9
Views
889
  • Introductory Physics Homework Help
Replies
20
Views
337
  • Introductory Physics Homework Help
Replies
7
Views
355
  • Introductory Physics Homework Help
3
Replies
95
Views
4K
  • Introductory Physics Homework Help
Replies
8
Views
3K
  • Introductory Physics Homework Help
Replies
12
Views
2K
  • Introductory Physics Homework Help
Replies
21
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
639
  • Introductory Physics Homework Help
Replies
7
Views
2K
Back
Top