- #1
jackattack825
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- Homework Statement
- The UPS person is delivering two rectangular boxes to the 4th floor of a building. The boxes are stacked vertically in the elevator. The one on the bottom has a mass of 5.00 kg and the one on the top has a mass of 2.00 kg. The elevator, the UPS person, and both boxes are accelerating upward at 2.50 m/s^2. What is the magnitude of the normal force between the two boxes?
- Relevant Equations
- Force(net) = mass * acceleration
Σ F= -F(gravity from earth) + F(normal from earth) -F(normal from top box) +F(normal from bottom box) = (2+5) * 2.5
The forces from gravity and it's normal force cancel out, leaving us with the normal forces from the boxes.
F(net of normal from boxes) = (2+5) * 2.5
= 17.5N
The forces from gravity and it's normal force cancel out, leaving us with the normal forces from the boxes.
F(net of normal from boxes) = (2+5) * 2.5
= 17.5N