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science.girl
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Homework Statement
A photon of wavelength 250 nm ejects an electron from a metal. The ejected electron has a de Broglie wavelength of 0.85 nm.
(a) Calculate the kinetic energy of the electron.
Homework Equations
KE = .5mv^2
The Attempt at a Solution
Which answer is correct?
ANSWER1: E = .5mv^2 and v = h/m[tex]\lambda[/tex]
Therefore, E = .5m(h/[tex]\lambda[/tex])^2
Substituting values (including [tex]\lambda[/tex] = .85*10^(-9)), you get 3.34*10^(-19) J
ANSWER2: wavelength=h/p=h/rad(2mK)
250e-9=6.63e-34/(2*9.11e-31K)
K=6.87e-4 Joules