- #1
Fewmet
- 406
- 37
There is a simple chemistry experiment for finding the fraction of air that is oxygen. You push some steel wool to the bottom of a graduated cylinder. Partly fill the cylinder with water, and invert the tube into a water reservoir such that the steel wool is now above a pocket of air that is above a raised column of water. (Here is an online account with a http://www.practicalchemistry.org/experiments/intermediate/oxidation-and-reduction/how-much-air-is-used-during-rusting,208,EX.html" ). As the steel wool rusts, oxygen is depleted and the water level rises.
The chem class I teach is wrestling through problems with this and variations on the experiment. We are having trouble with one student question: what is the relationship involving the pressure exerted down by the gas trapped in the tube (Pi), the atmospheric pressure acting on the water in the reservoir,(PA) and the [tex]\rho[/tex]gh pressure of the water column in the cylinder? Is it simply that the three sum to zero?
The chem class I teach is wrestling through problems with this and variations on the experiment. We are having trouble with one student question: what is the relationship involving the pressure exerted down by the gas trapped in the tube (Pi), the atmospheric pressure acting on the water in the reservoir,(PA) and the [tex]\rho[/tex]gh pressure of the water column in the cylinder? Is it simply that the three sum to zero?
Last edited by a moderator: