- #1
Enharmonics
- 29
- 2
Homework Statement
Determine Currents ##I_{1}, I_{2}, I_{3}##
Homework Equations
Kirchoff's Rules:
$$\sum_{i=1}^n I_{i} = 0$$
$$\sum_{i=1}^n V_{i} = 0$$
The Attempt at a Solution
Basically, I'm not sure if I'm applying the Loop Law correctly. For example, in Loop A, going clockwise from the upper leftmost corner of the circuit, it's easy enough to see that I'd have ##-\epsilon_{1}## and ## +I_{1}R_{1}## based on the direction I'm "tracing" the circuit in, but when I come to the first junction, ##J_{1}##, I'm not sure what to do.
Applying Kirchoff's Junction rule to it based on the entirety of the circuit shows that
$$\sum_{i=1}^n I_{i} = I_{2} + I_{3} - I_{1} = 0 \rightarrow I_{1} = I_{2} + I_{3}$$
But ##I_{3}## isn't in Loop A... so then
$$\sum_{i=1}^n I_{i} = I_{2} - I_{1} = 0 \rightarrow I_{1} = I_{2}$$
I used a similar argument to set up my equation for Loop B.
Is the way I have my system of equations set up (in the image above) correct? If not, would I have to calculate the voltage drop using ##I_{2} = I_{1} - I_{3}##?
Using my current system of equations, my values for the currents are
##I_{1} = \frac{935}{626} A , I_{2} = \frac{205}{313} A, I_{3} = \frac{525}{626} A##
Is that correct?
Thanks in advance.