Potential of concentric cylindrical insulator & conducting shell. Stuck on 2nd question

V(c) is the potential at the outer surface of the conducting shell, which is equal to the potential at the outer surface of the insulator (since they are concentric). Therefore, V(c) - V(a) = 0.
  • #1
Richard Ros
18
0
An infinitely long solid insulating cylinder of radius a = 5.2 cm is positioned with its symmetry axis along the z-axis as shown. The cylinder is uniformly charged with a charge density ρ = 23 μC/m3. Concentric with the cylinder is a cylindrical conducting shell of inner radius b = 14.2 cm, and outer radius c = 16.2 cm. The conducting shell has a linear charge density λ = -0.45μC/m.

1. What is Ey(R), the y-component of the electric field at point R, located a distance d = 58 cm from the origin along the y-axis as shown?
-7897.28N/C

2. What's V(c)-v(a), the potential difference between the outer surface of the conductor and the outer surface of the insulator.
KQ
My Attempt : Vc - Va = kq/c - kq/a
vc - va = qk * (1/c - 1/a)
 
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  • #2
Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
 
  • #3
First find the E field using a gaussian surface, then integrate E from the cylinder to the shell.
 

1. What is the purpose of a concentric cylindrical insulator and conducting shell?

A concentric cylindrical insulator and conducting shell are used to create a uniform electric field within the space between them. This is useful in applications such as capacitors and particle accelerators.

2. How does the shape of the insulator and conducting shell affect the electric field?

The shape of the insulator and conducting shell plays a crucial role in determining the strength and direction of the electric field. The closer the two cylinders are to each other, the stronger the electric field will be between them.

3. Can the concentric cylindrical insulator and conducting shell be used in high voltage applications?

Yes, these components are often used in high voltage applications as they are able to withstand large electric fields without breaking down. The insulator acts as a barrier to prevent current from flowing between the two cylinders.

4. How does the material of the insulator and conducting shell affect their performance?

The material of the insulator and conducting shell can impact their performance in terms of their ability to withstand high voltages and their dielectric strength. Materials with high dielectric strength, such as ceramics, are often used in these components.

5. Are there any limitations to using a concentric cylindrical insulator and conducting shell?

One limitation is that the electric field between the two cylinders is only uniform in the space between them. Outside of this space, the electric field may not be as uniform. Additionally, the shape and size of the components may limit their use in certain applications.

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