Probability of at Least One Girl in a Five-Child Family | Independent Births

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In summary, the conversation is about a question regarding the probability of a family having at least one girl, given that they have at least one boy. The discussed solution is 1-(1/2)^4 = 15/16, but according to the book, the correct answer is 30/31. The solution is found by looking at the binomial distribution and considering the different combinations of genders in a family of five children. The problem states that the family has at least one boy, so the formula for conditional probability should be used.
  • #1
tramp
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Hi
I have some difficulties with following question.

A family has five children. Assuming that the probability of a girl on each birth was 1/2 and that the five births were independent, what is the probability the family has at least one girl, given they have at least one boy?

My solution is 1-(1/2)^4 = 15/16

However according to the book correct answer it 30/31.
Any ideas?
 
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  • #2
tramp said:
Hi
I have some difficulties with following question.

A family has five children. Assuming that the probability of a girl on each birth was 1/2 and that the five births were independent, what is the probability the family has at least one girl, given they have at least one boy?

My solution is 1-(1/2)^4 = 15/16

However according to the book correct answer it 30/31.
Any ideas?

Look at material on the binomial distribution.

The conditions in the problem are satisified if the family has any of the following combinations of genders:
(exactly 1 boy and 4 girls)
(exactly 2 boys and 3 girls)
(exactly 3 boys and 2 girls)
(exactly 4 boys and 1 girl)

The conditions are not satisfied by the combinations of genders:
(exactly 5 boys and 0 girls )
(exactly 0 boys and 5 girls )

The problem says we are "given" that the family has at least one boy, so you should look at the formula for conditional probability.
 
  • #3
Thanks a lot Stephen.
I figured it out. Your post was a great help.
 

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