Proof of angular momentum conservation

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The discussion focuses on understanding the derivation of angular momentum conservation in the context of Lagrangian and Hamiltonian mechanics. The user is confused about the differentiation of the angular momentum expression, specifically why certain terms are omitted in the derivation. They also seek clarification on the mathematical manipulation that leads to the equation ri X Fji = 1/2(rij X Fji) for two particles. The conversation highlights the importance of understanding these derivations to grasp the principles of torque and angular momentum. Clear explanations of these concepts are essential for a deeper comprehension of the mechanics involved.
KT KIM
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This is from text [Introduction to Lagrangian and Hamiltonian Mechanics] on NTNU opencourse.
Annnnd... I don't use english as my primary language, so sorry for poor sentences.

I can't get two things in here.

First, at (1.12) I can't understand how L dot derivated like that.
Since I know differentiation of cross product should be done like

d/dt(AxB)=d/dt(A) x B + A x d/dt(B)

then, at (1.12), why it doesn't have the terms of d/dt(r) x p ?
I think it only has the terms of r x d/dt(p)

Second, I can't get how
upload2.png

were derived by using (1.13), How could ri X Fji = 1/2(rij X Fji)
is possible?

These might be dumb questions, but please help me.
 
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KT KIM said:
en, at (1.12), why it doesn't have the terms of d/dt(r) x p ?
##\boldsymbol p_i=m_i\dot{\boldsymbol r}_i,\quad \dot{\boldsymbol r}_i\times\dot{\boldsymbol r}_i=0##
by the way ##\sum_{ij}{\boldsymbol r}_{i}\times\boldsymbol F_{ji}=0##
 
Thank you for clear explanation. Got the first one.

Yes Σij rij x Fji = 0 so eventually it makes L dot = tau (torque)
But, what I want know is the mathematical manuever that makes ri X Fji = 1/2(rij X Fji)
 
do the calculation for two particles directly and everything will be clear
 
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