What is Momentum conservation: Definition and 238 Discussions

In Newtonian mechanics, linear momentum, translational momentum, or simply momentum (pl. momenta) is the product of the mass and velocity of an object. It is a vector quantity, possessing a magnitude and a direction. If m is an object's mass and v is its velocity (also a vector quantity), then the object's momentum is





p

=
m

v

.


{\displaystyle \mathbf {p} =m\mathbf {v} .}
In SI units, momentum is measured in kilogram meters per second (kg⋅m/s).
Newton's second law of motion states that the rate of change of a body's momentum is equal to the net force acting on it. Momentum depends on the frame of reference, but in any inertial frame it is a conserved quantity, meaning that if a closed system is not affected by external forces, its total linear momentum does not change. Momentum is also conserved in special relativity (with a modified formula) and, in a modified form, in electrodynamics, quantum mechanics, quantum field theory, and general relativity. It is an expression of one of the fundamental symmetries of space and time: translational symmetry.
Advanced formulations of classical mechanics, Lagrangian and Hamiltonian mechanics, allow one to choose coordinate systems that incorporate symmetries and constraints. In these systems the conserved quantity is generalized momentum, and in general this is different from the kinetic momentum defined above. The concept of generalized momentum is carried over into quantum mechanics, where it becomes an operator on a wave function. The momentum and position operators are related by the Heisenberg uncertainty principle.
In continuous systems such as electromagnetic fields, fluid dynamics and deformable bodies, a momentum density can be defined, and a continuum version of the conservation of momentum leads to equations such as the Navier–Stokes equations for fluids or the Cauchy momentum equation for deformable solids or fluids.

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  1. weafq

    I Energy and momentum of a photon in a medium

    According to this paper: https://academicjournals.org/article/article1380534636_Salih.pdf, the researcher states that energy of a photon is dependent on a medium while momentum of a photon is independent. However according to https://arxiv.org/ftp/physics/papers/0607/0607094.pdf, the research...
  2. L

    Would conservation of momentum apply in this vehicle accident homework problem?

    Vehicle A Before collision = (mass of driver + mass of vehicle A) x velocity = (50+1000) x 20 =21000kgm/s After collision = (mass of driver x v) + (mass of vehicle A x 0) =50v +0 =50v 50v = 21000 v=420m/s Vehicle B Before collision = (mass of driver + mass of vehicle B) x velocity = (50+500) x...
  3. E

    What is the right formula to use in this context? (momentum conservation)

    First i think the correct solution to the problem is But my friends argue that it is not what i did , i am confused we didn't see the whole chapter on momentum in class, (Youtube thank you) here is what my friends say : (0.3×5) + 0 = (V×0.3)+(0.4×2) and they get they a final speed of 2.33...
  4. resurgance2001

    Conservation of momentum for a robot on a space platform

    The momentum of the robot is 95.0 x 1.4 m/s towards the platform. This must be equal and opposite to the momentum imparted to the beam. Dividing 133 kg m/s by 330.0 Kg gives a velocity of 0.403 m/s for the beam. So the relative velocity of the robot relative to the platform is 1.40 - 0.403 =...
  5. cianfa72

    I About the use of nominal definitions in physics

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  6. Clueless_2

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  7. Jeavenasti

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  8. M

    Solving Elastic Collision of Two Balls: Theory & Solutions

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  9. Kyuubi

    Solving Orbital Speed with Energy & Angular Momentum Conservation

    I've already solved the orbital speed by equating the kinetic and potential energy in the circle orbit case. $$\frac{1}{2}mv^2 = \frac{1}{2}ka^2.$$And so $$v^2 = \frac{k}{m}a^2$$Now when the impulse is added, the particle will obviously change course. If we set our reference point in time just...
  10. C

    Puck collision with rod using angular momentum conservation

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  11. H

    Conservation of Momentum of Rocket Exploding after Takeoff

    -Solved for vf using equation 3 to get 20.0m/s (speed before explosion) then solved for the distance to reach the explosion using equation 4, to get 20.0m, which felt wrong having the same numbers but that may just be coincidence. -Found the distance travelled of the lighter piece using 530m -...
  12. person123

    I Momentum of a Water Jet Impacting Plate

    Suppose you have a jet of fluid (say water) traveling vertically upward at a constant velocity. It impacts a stationary horizontal plate and so moves radially outward in all directions. Assume that there's no energy loss during the impact, so the speed of the fluid remains constant. Is momentum...
  13. mr_sparxx

    I Kepler's second law derivation from angular momentum conservation

    Many texts state that in an elliptic orbit you can find angular momentum magnitude as $$ L = r m v = m r^2 \frac {d \theta} {dt} $$ I wonder if $$ v = r \frac {d \theta} {dt} $$ is valid at every point. I understand this approximation in a circumference or radius r but what about an arc...
  14. Delta2

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  15. Shreya

    Momentum Conservation: Bullet enters a block

    I can understand that using conservation of momentum, we can find v. But we need V for that. The equation for V involves h and so we need h. But I am not able to comprehend the equation involving l,h and a. The question doesn't specify what a is. Please be kind to help
  16. E

    I Momentum conservation for EM-Field/matter interaction

    Hello, I'm reading Feynman Lectures Vol II, and saw this "paradox" in section 26-2 (Figure 26-6), where two orthogonally moving charges can be shown to have unequal action and reactions. Later in Chapter 27, the explanation was given briefly citing field momentum. I tried to prove this...
  17. mattlfang

    A bullet collides perfectly elastically with one end of a rod

    A bullet with mass m, velocity v perfectly elastically, vertically collide with one end of a rod on a slippery plane and the bullet stops moving after the collision. Find the mass of the stick M the bullet stops moving after an elastic collision, so all energy is transformed to the rod. There...
  18. greg_rack

    Engineering Solving Momentum Conservation Problems: Tips & Tricks

    Hello guys, could someone give me a small hint to get me started on attempting this problem? I really cannot figure out how to relate conservation of momentum to the fact that there shouldn't be friction... does it have something to do with the so-called "sweet spot" of the ball? But then...
  19. P

    I Can I suck myself forward with a straw when floating in air?

    I find myself in a space with air but no gravity. Say at ISS. Can I suck myself forward by sucking a straw? It reminds me somehow of Feynman's sprinkler. Also Mach looked at something like Feynman's sprinkler. Mach invented something alike. Four ex/inhalers of air, tubes, that are in/exhale air...
  20. M

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    I aready got the solution for this exercise. However, the solution used the referance frame from the car: What I'm trying to understand is the line: Because before reading the solution, I was trying to solve it using the lab frame. So this is my work so far: Using conservation of momentum and...
  21. S

    Momentum Conservation: How to Reconcile a Negative Value?

    Maybe a silly question but on the above question using the conservation of momentum: momentum before firing (0) = momentum after firing (55*35)+(M*2.5) If I re-range the above it's M = -(55*35)/2.5 = -770kg. I can I reconcile that minus sign (basically get rid of it)? Thanks
  22. Ayandas1246

    Conceptual questions about Angular Momentum Conservation and torque

    List of relevant equations: Angular Momentum = L (vector) = r(vector) x p(vector) Angular velocity of rotating object = w(vector), direction found using right hand rule. Torque = T(vector) = dL(vector)/dt I have a few questions about torque and angular momentum direction and...
  23. burian

    Application of momentum conservation in inelastic collisions

    So, what I did was suppose the mass of ramp is $ M_r$ and let velocity at B of block be v, then, after inellastic collsion both bodies v' velocity at B , $$M\vec{v}= M_r \vec{v'}+ M \vec{v'}$$ or, $$ \frac{M}{M +M_r} \vec{v}= \vec{v'}$$ Now, Suppose I take the limit as mass of ramp goes to...
  24. Prabs3257

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  25. D

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  26. A

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  27. LCSphysicist

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    Angular momentum can be exchanged between objects in a closed system, but total angular momentum before and after an exchange remains constant (is conserved). There is a proof about this conservation?
  28. Like Tony Stark

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  29. C

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  30. JD_PM

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  31. Sabra_a

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  32. Kaushik

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  33. yash_it_is

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    I want to ask why is it that we use gauge pressure instead of absolute pressure in CV analysis for momentum conservation of fluids. I did read that because P(atm) would be present everywhere so it won't have a net effect on the CV but it's highly non intuitive as I can't apply force balance on...
  34. Shivam

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  35. Alfredo Tifi

    I The Symmetry of Angular Momentum Conservation

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  36. PainterGuy

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  37. jehwig0107

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  38. brotherbobby

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  39. E

    Angular momentum conservation and center of mass

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  40. Cc518

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  41. T

    Forces - Space Shuttle Takeoff Calculations

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  42. delta76

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  43. J

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  44. M

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    Homework Statement A rod of length D sits at rest on a friction less table. A ball of mass M strikes the end of the rod with a speed V and rebounds with a speed 3v/4 causing the rod to rotate counterclockwise around a fixed axis at one end. The rotational inertia of the rod is I Homework...
  45. C

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  46. Krushnaraj Pandya

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    Homework Statement suppose you're sitting on a rotating stool holding a 2kg mass in each outstretched hand, if you suddenly drop the masses, will your angular velocity increase, decrease or remain the same? Homework Equations dL/dt=net torque when net torque is 0, L=constant=Iw therefore...
  47. Krushnaraj Pandya

    Momentum conservation: block-wedge problem

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  48. A

    Analyzing Elastic Collisions w/ Conservation of Energy and Momentum

    Homework Statement There is a 4 kg mass that has a speed of 6 m/sec on a horizontal frictionless surface. The mass collides head-on and elastically with an identical 4 kg mass initially at rest. The final speed of the first 4 kg mass is: (a) 0 m/s (b) 2 m/s (c) 3 m/s (d) 6 m/s Homework...
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