Prove Continuity of g: A Continuity Problem Homework Statement

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In summary, the conversation discusses proving the continuity of a function g, which is defined as the limit of the function f. The goal is to show that for any given point a, the limit of g at a is equal to the limit of f at a. To do this, the speaker discusses finding values for d and d' that satisfy certain inequalities involving f and g. However, there is a challenge in manipulating these inequalities due to the different intervals in which they are true.
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Homework Statement
Let f be a function with the property that every point of discontinuity is a removable discontinuity. This means that [tex]\lim_{y\to x} f(y)[/tex] exists for all x, but f may be discontinuous at some (even infinitely many) numbers x. Define [tex]g(x) = \lim_{y\to x} f(y)[/tex]. Prove that g is continuous.

The attempt at a solution
So I have to prove that for all a,

[tex]\lim_{x \to a} g(x) = \lim_{x \to a} \lim_{y\to x} f(y) = g(a) = \lim_{y\to a} f(y) [/tex]

In other words, for every e > 0, there is a d > 0 such that

[tex]\left| \lim_{y\to x} f(y) - \lim_{y\to a} f(y) \right| < e[/tex]

for all x satisfying |x - a| < d. I have no clue how to find d. Any tips.
 
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  • #2
I think you are going to need to reduce the two limits in your last inequality to their definitions.
 
  • #3
OK. So let d' be such that |f(y) - g(x)| < e for all y with |y - x| < d' and let d'' be such that |f(y) - g(a)| < e for all y with |y - a| < d''.

The problem now is that I can't fiddle around with |f(y) - g(x)| < e and |f(y) - g(a)| < e because there are different intervals where these inequalities are true.
 

Related to Prove Continuity of g: A Continuity Problem Homework Statement

1. What is the definition of continuity?

Continuity is a mathematical concept that describes the smoothness or "connectedness" of a function. A function is considered continuous if there are no sudden jumps or breaks in its graph.

2. How do you prove continuity of a function?

To prove the continuity of a function, you must show that the function is defined at a particular point, the limit of the function at that point exists, and the limit is equal to the value of the function at that point. This can be done using the epsilon-delta definition of continuity or by using theorems such as the Intermediate Value Theorem and the Squeeze Theorem.

3. What is the epsilon-delta definition of continuity?

The epsilon-delta definition of continuity states that a function f(x) is continuous at a point a if, for any given positive number epsilon, there exists a positive number delta such that for all x within delta distance from a, the difference between f(x) and f(a) is less than epsilon. In other words, small changes in x result in small changes in f(x).

4. How is continuity related to differentiability?

Continuity and differentiability are closely related concepts. A function must be continuous at a point in order to be differentiable at that point. This means that the function must not have any sudden jumps or breaks in its graph at that point. However, a function can be continuous without being differentiable, as is the case with functions that have a sharp corner or cusp at a particular point.

5. Can a function be continuous but not have a continuous derivative?

Yes, a function can be continuous but not have a continuous derivative. This can occur when the derivative of the function has a discontinuity or does not exist at a particular point. An example of this is the absolute value function, which is continuous but has a discontinuous derivative at x = 0.

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