- #1
sonadoramante
- 19
- 3
Proof:
Let a be a even positive integer of the form a=2m & b of the form b=2n (This is where b is a even positive integer)
ab = 2m*2n
= 2(mn)
= Let k = mn
= 2k
Therefore, ab is even.
Let a be a even positive integer a=2m & b be a odd positive integer b = 2n+1
ab = (2m)*(2n+1)
= 4mn + 2m
= 2(mn+m)
= Let k = (mn+m)
= 2k
Hence ab is even.
Let a be a even positive integer of the form a=2m & b of the form b=2n (This is where b is a even positive integer)
ab = 2m*2n
= 2(mn)
= Let k = mn
= 2k
Therefore, ab is even.
Let a be a even positive integer a=2m & b be a odd positive integer b = 2n+1
ab = (2m)*(2n+1)
= 4mn + 2m
= 2(mn+m)
= Let k = (mn+m)
= 2k
Hence ab is even.