- #1
sonadoramante
- 19
- 3
Summary:: Prove that if a is an odd integer and b is an odd integer then a+b is even.
Theorem: If a is odd and b is odd then a+b is even.
Proof: Let a and b be positive odd integers of the form a = 2n+1 & b = 2m+1
a+b = 2n+1+2m+1
= 2n+2m+1+1
= 2n+2m+2
= 2(n+m)+2
= Let k = n+m
= 2k+2
Therefore a+b is even.
Theorem: If a is odd and b is odd then a+b is even.
Proof: Let a and b be positive odd integers of the form a = 2n+1 & b = 2m+1
a+b = 2n+1+2m+1
= 2n+2m+1+1
= 2n+2m+2
= 2(n+m)+2
= Let k = n+m
= 2k+2
Therefore a+b is even.