- #1
goggles31
- 34
- 0
Cv = (∂U/∂T)v = T(∂S/∂T)v
I can prove this by using the Maxwell relations, but I have trouble deriving it from the first law.
dU = TdS - pdV
(∂U/∂T)v = T(∂S/∂T)v + ∂S(∂T/∂T)v = T(∂S/∂T)v + ∂S
Is there a problem with my derivation?
I can prove this by using the Maxwell relations, but I have trouble deriving it from the first law.
dU = TdS - pdV
(∂U/∂T)v = T(∂S/∂T)v + ∂S(∂T/∂T)v = T(∂S/∂T)v + ∂S
Is there a problem with my derivation?