- #1
Miike012
- 1,009
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I have an easy question which I've been thinking about for a while..
Lets say I want to take the derivative of a function y = f(x) with respect to x, we would get.
dy/dx = f'(x).
In the couple of books I've skimmed through, they all say that dy/dx is not a ratio but the notation that implied taking the derivative of y with respect to x.
Question:
If dy/dx is not a ratio then how come the differential of y is equal to f'(x)dx? It almost seems as they are multiplying both sides by dx. This can't be mathematically correct, can it? I would like to know mathematically how dy is equal to f'(x)dx.
Lets say I want to take the derivative of a function y = f(x) with respect to x, we would get.
dy/dx = f'(x).
In the couple of books I've skimmed through, they all say that dy/dx is not a ratio but the notation that implied taking the derivative of y with respect to x.
Question:
If dy/dx is not a ratio then how come the differential of y is equal to f'(x)dx? It almost seems as they are multiplying both sides by dx. This can't be mathematically correct, can it? I would like to know mathematically how dy is equal to f'(x)dx.