Question about the Derivation of the Equations of Vibration

In summary, the differential equation yields the following two solutions:u = Acosωt + Bsinωtu = RcosΦcosωt + RsinΦsinωt
  • #1
Amadeo
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TL;DR Summary
Derivation of Equation of Vibration
For undamped free vibrations, we have the following differential equation.

mu'' + ku = 0

where m is the mass of the object hanging on the end of a spring, and u is the distance from the equilibrium position as a function of time.

This yields u = Acosωt + Bsinωt

where ω is √(k/m) (k=spring constant).

I am having trouble understanding why this can be rewritten as

u = RcosΦcosωt + RsinΦsinωt (which, in turn, = Rcos(ωt -Φ) )

If A represents the initial displacement from equilibrium (ui), I can see how we could set this equal to RcosΦ, (R being the maximum displacement) thereby defining Φ to be that value which makes ui=RcosΦ true. But, I don't see why B must, in that case, necessarily be RsinΦ.

It looks like B must be the initial velocity (vi) multiplied by m/k.
 
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  • #2
This just occurred to me:

Since the solution u = Acosωt + Bsinωt is general, A and B can be any two constants. If we choose two arbitrary constants for A and B, this will determine the initial displacement and the initial velocity.

Alternatively, if we choose two arbitrary values for the initial displacement and velocity, these will determine A and B.

In this case, we are choosing values for A and B. These values then determine the initial velocity and displacement. We could choose any values we wish, but we chose these values (A= RcosΦ and B=RsinΦ) because they enable the convenient reformulation Rcos(ωt -Φ).

Any more insights would be appreciated.
 
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  • #3
You mentioned a mass hanging from a spring and its displacement (m,k,u). The solution is Acosωt + Bsinωt where both A and B have displacement units. I understand those. The R and Φ look like polar coordinates, range and angle. Does your spring hang from a pivot? Describe exactly what is vibrating.
 
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  • #4
Amadeo said:
This just occurred to me:

Since the solution u = Acosωt + Bsinωt is general, A and B can be any two constants. If we choose two arbitrary constants for A and B, this will determine the initial displacement and the initial velocity.

Alternatively, if we choose two arbitrary values for the initial displacement and velocity, these will determine A and B.

In this case, we are choosing values for A and B. These values then determine the initial velocity and displacement. We could choose any values we wish, but we chose these values (A= RcosΦ and B=RsinΦ) because they enable the convenient reformulation Rcos(ωt -Φ).

Any more insights would be appreciated.

Another way to look at it: the set ##(A, B)## is just the set of any two numbers. You could think of this as points in a plane expressed in Cartesian coordinates. Equally, you could express this in polar coordinates ##(R\cos \phi, R \sin \phi)##, where ##R^2 = A^2 + B^2## etc.
 
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1. What is the purpose of deriving equations of vibration?

The purpose of deriving equations of vibration is to understand the behavior and motion of vibrating systems. These equations can be used to predict the amplitude, frequency, and other characteristics of vibrations, which is important in fields such as engineering, physics, and acoustics.

2. How are equations of vibration derived?

Equations of vibration are typically derived using mathematical principles, such as Newton's laws of motion and Hooke's law. The process involves analyzing the forces and displacements acting on a vibrating system and using these relationships to develop equations that describe its motion.

3. What factors affect the equations of vibration?

The equations of vibration are affected by various factors, including the mass, stiffness, and damping of the vibrating system. These parameters can influence the natural frequency, amplitude, and behavior of the vibrations.

4. Can the equations of vibration be applied to all types of systems?

The equations of vibration can be applied to a wide range of systems, including mechanical, electrical, and acoustic systems. However, the specific equations and parameters used may vary depending on the type of system and its characteristics.

5. How accurate are the equations of vibration?

The accuracy of the equations of vibration depends on the assumptions and simplifications made during the derivation process. In some cases, these equations may provide a good approximation of the actual behavior of a vibrating system, while in others, they may only be valid under certain conditions.

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