no , i use Q= (L^3) / T , so Qr = (Lr^3) / Tr , am i right ?Simon Bridge said:Please explain your reasoning... I am not following your notation.
If we say that the flow rate in the model is q = kr^3/T (here k is a constant of proportionality, r is a characteristic length, and T is time) and the flow rate in the prototype is Q=kR^3/T ... then Q/q=?? and R/r=??
i am not sure Lp / Lm or Lm / Lp = 10 ... can you explain ?Simon Bridge said:Please explain your reasoning... I am not following your notation.
If we say that the flow rate in the model is q = kr^3/T (here k is a constant of proportionality, r is a characteristic length, and T is time) and the flow rate in the prototype is Q=kR^3/T ... then Q/q=?? and R/r=??
scale modelSimon Bridge said:I don't know what your variables mean: you have to tell me. If you do not answer questions I cannot help you.
Guessing: Q=L^3/T where Q is the flow rate, L is some characteristic length, and T is time.
Is this correct?
Are you using two-letter variable names (this is bad practise)?
So that Qm is the flow rate through the model?
Thus Qm = Lm^3/T and Qp=Lp^3/T for the model and the prototype respectively.
Thus: complete the following: Qp/Qm =?? and Lp/Lm=??
Consider: which is usually smaller - the scale model or the prototype?
If you do not tell me what these letters mean I cannot help you.i want to find the Qm thru the relationship of Qp / Qm = (Lr^3) / Tr ,
where Tr = Tp / Tm , Lr = Lp / Lm
Q = flow rate , T = time , L = lengthSimon Bridge said:If you do not tell me what these letters mean I cannot help you.
Don't make me guess!
Tr = ratio of time of prototype to model , Lr = ratio of length of prototype to model , Qr = ratio of flow rate of prototype to modelSimon Bridge said:If you do not tell me what these letters mean I cannot help you.
Don't make me guess!
ya , i know that . for the scale ratio 10; 1 , it means Lp / Lm = 10 ?Simon Bridge said:OK: use the same time period to measure Qm and Qp, so Tr=1.
... you can work it out: you have already said that the prototype has to be bigger than the model.for the scale ratio 10; 1 , it means Lp / Lm = 10 or Lm / Lp = 10 ? i am confused.
so , the prototype must be bigger than the model ??Simon Bridge said:... you can work it out: you have already said that the prototype has to be bigger than the model.
This means that Lp > Lm
Lp/Lm = 10 means Lp=10*Lm
Lm/Lp = 10 means Lm=10*Lp
... so which is right? Which one means that Lp > Lm?
The purpose of determining the ratio of size between a prototype and a model is to accurately represent the final product or system in a smaller scale. This allows for testing and evaluation of the design before investing time and resources into the full-scale version.
The ratio of size is typically calculated by dividing the actual size of the prototype by the size of the model. For example, if the prototype is 10 inches and the model is 2 inches, the ratio would be 10:2 or 5:1.
Some factors to consider when determining the ratio of size between a prototype and a model include the level of detail needed, the materials being used, and the purpose of the model (e.g. for display or for testing).
It is not always necessary to maintain the exact same ratio of size between a prototype and a model. Depending on the purpose of the model, it may be beneficial to modify the ratio to better suit the needs of the project.
Yes, the ratio of size can have an impact on the accuracy of the final product. If the ratio is not accurately determined or maintained, it can result in discrepancies between the prototype and the final product. It is important to carefully consider and calculate the ratio to ensure the final product is as accurate as possible.