Relation between 'P' and 'V' for an Adiabatic process

In summary: When the ratio of gamma is high, the efficiency of the engine is higher.In summary, the conversation discusses the derivation of the equation PV γ = constant and the physical significance of the heat capacity ratio (gamma) on a curve of PV γ = constant. The equation is derived by substituting the internal energy from an isochoric process into an adiabatic process and represents the relationship between pressure, volume, and the heat capacity ratio of an ideal gas. The heat capacity ratio is important in cyclic processes, such as a heat engine, as it affects the efficiency of the engine.
  • #1
Dr. Who
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Hi All,

I have a little query concerning the derivation of PV γ = constant. In my textbook of Physics, first they give the equation for adiabatic process using the first law of Thermodynamics, as;

dEint = W → (1)​

where,
ΔEint ⇒ change in internal energy and W ⇒ workdone
Then, they used the relation:

Cv = Q / ndt​
Where,
Q ⇒ heat
'n' ⇒ no. of moles
Cv ⇒ Molar Heat capacity at constant volume
dT ⇒ Change in temperature

Now, for an isochoric process;
Q = dEint
dEint = nCvdT → (2)​

Substituting dEint from eq.(2) into eq.(1)

⇒ W = nCvdT​

As thermodynamic work is given as W = -PdV
∴ -PdV = nCvdT
⇒ PdV = - nCvdT → (3)​

Now, writing equation of state of the gas in differential form as;
d(PV) = d(nRT)​
⇒ PdV + VdP = nRdT​
Using eq.(3)
⇒ - nCvdT + VdP = nRdT
⇒ VdP = nCvdT + nRdT​

Using the relation Cp = Cv + R into the above equation

⇒ VdP = nCpdT → (4)​

Now, dividing eq.(4) by eq.(3)
⇒ VdP / PdV = -Cp / Cv
or VdP / PdV = -γ
where, γ ⇒ ratio of molar heat capacities

Rearranging the above equation:
dP / P = -γ dV / V​
Integrating both sides with the initial state 'i' and final state 'f' being the lower and upper limits respectively, gives;

dP / P = -γ dV / V​

⇒ PiViγ = PfVfγ

which can be written as: PV γ = constant

Now, my query was that,
1. why have they substituted the internal energy from an isochoric process into an adiabatic process (Substituting dEint from eq.(2) into eq.(1))? Considering this substitution, can we say that heat absorbed in the isochoric process is equivalent to the work done in an adiabatic process?

2. What is the physical significance of γ on a curve of PV γ = constant ? (Please do not go into the details of poltropic processes)
 
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  • #2
Dr. Who said:
1. why have they substituted the internal energy from an isochoric process into an adiabatic process (Substituting dEint from eq.(2) into eq.(1))? Considering this substitution, can we say that heat absorbed in the isochoric process is equivalent to the work done in an adiabatic process?

2. What is the physical significance of γ on a curve of PV γ = constant ? (Please do not go into the details of poltropic processes)
For an isochoric process the work done is always zero.
A typical example of an isochoric process is addition or removal of heat from a closed system.
The volume remains constant but temperature and pressure change according to the process.
thus leading to change in internal energy.

An adiabatic system is perfectly insulated from external environment and there is no heat transfer in or out of the system.
Work done in an adiabatic process completely results in change in the internal energy of the system.
so the two processes can be related.The heat capacity ratio(gamma) for an ideal gas can be related to the degrees of freedom of a molecule of gas

gamma = 1 + 2/(degree of freedom )
for a monoatomic gas, degree of freedom is 3 so its value is (1 +2/3) = 1.67
and for diatomic gas it (gamma) goes to 1.4 as the gas has five degrees of freedom.
This ratio becomes important when one uses the gas in a cyclic process for conversion of heat into work. and gas is taken as working substance like in a heat ( carnot engine.) engine.
 
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1. What is the relation between 'P' and 'V' for an Adiabatic process?

The relation between pressure ('P') and volume ('V') for an Adiabatic process is described by the equation P^γ = constant, where γ is the ratio of specific heats for the gas undergoing the process. This means that as the volume of the gas decreases, the pressure increases and vice versa, while maintaining a constant value for P^γ.

2. How does an Adiabatic process differ from an Isothermal process?

An Adiabatic process is one in which no heat is exchanged between the system and its surroundings, while an Isothermal process is one in which the temperature remains constant. In an Adiabatic process, the change in internal energy is solely due to work being done on or by the system, whereas in an Isothermal process, the change in internal energy is solely due to heat transfer.

3. Is the relation between 'P' and 'V' the same for all gases in an Adiabatic process?

No, the relation between 'P' and 'V' for an Adiabatic process depends on the specific gas undergoing the process and its ratio of specific heats (γ). This means that the value of the constant in the equation P^γ = constant will vary for different gases.

4. What is the significance of the Adiabatic process in thermodynamics?

The Adiabatic process is significant in thermodynamics because it allows us to understand the behavior of a system when no heat is exchanged with its surroundings. This is important in many real-world scenarios, such as in the operation of engines and the compression of gases, where heat transfer may be minimal or negligible.

5. How is the work done in an Adiabatic process related to the change in internal energy?

In an Adiabatic process, the work done on or by the system is equal to the change in internal energy (ΔU) of the system. This is because, as mentioned earlier, the change in internal energy is solely due to work being done on or by the system, and there is no heat transfer involved. This relationship is described by the equation W = ΔU = PΔV.

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