Relationship between inertial and gravitational mass?

In summary: The policy is designed to discourage students from posting personal and speculative theories, which are not appropriate for Physics forums.
  • #1
Sturk200
168
17
I should preface this question by saying that I am not familiar with Einstein's general relativity, so I am trying to understand the relationship between gravitational and inertial mass from a purely classical standpoint.

Newton writes that the gravitational force exerted by an object is proportional to that object's inertial mass. As far as I know the only reliable way to define or measure mass is by measuring the acceleration caused by the application of a known force and quantifying this with respect to a reference mass. Thus inertial mass is defined as an object's ability to resist being accelerated or decelerated by some force.

Applying this definition of mass to the law of universal gravitation, we find that the gravitational force associated with some object is proportional to that object's ability to resist being moved by a force. This seems like too straightforward a connection to be merely coincidental. My question then is this, how are we to understand the relationship between inertial mass and gravitational mass? Particularly, is it possible that an object gains its ability to resist being moved by a force (i.e. gains its inertial mass) by virtue of the fact that it is pulled by a contrary gravitational force towards surrounding objects?

For example, suppose we place a ping pong ball and a brass ball in space and subject them each to an identical force -- we project each with a spring loaded plate. The ping pong ball is projected faster and farther than the brass ball. We want to say this is because the brass ball is more massive. But is it possible that all we are expressing in this statement is that, due to gravity, the brass ball is attracted to the spring loaded plate with a greater force than the ping pong ball, and is therefore endowed with a greater ability to resist the force of the spring?
 
Physics news on Phys.org
  • #2
Sturk200 said:
This seems like too straightforward a connection to be merely coincidental.
Indeed it is, and it intrigued people for better than two centuries after Newton discovered it. It was finally explained by Einstein when he discovered general relativity.
My question then is this, how are we to understand the relationship between inertial mass and gravitational mass? Particularly, is it possible that an object gains its ability to resist being moved by a force (i.e. gains its inertial mass) by virtue of the fact that it is pulled by a contrary gravitational force towards surrounding objects?
No, that is not the explanation. The way to understand the relationship between inertial and gravitational mass is to learn general relativity; you can't explain it from a classical standpoint for about the same reasons that you can't explain how smoke is formed without considering fire.
 
  • #3
Nugatory said:
No, that is not the explanation. The way to understand the relationship between inertial and gravitational mass is to learn general relativity; you can't explain it from a classical standpoint for about the same reasons that you can't explain how smoke is formed without considering fire.

I don't know if the relationship between the curvature of spacetime and universal gravitation is quite as simple as that between fire and smoke, but I take your point and look forward to learning general relativity.

For now, are there concrete reasons that the explanation is incorrect? I wrote the question hoping that somebody with more expert vision might be able to demonstrate why it was wrong -- perhaps by seeing through to an inconsistent consequence -- and thereby correct the idea while enlightening the subject.
 
  • #4
Sturk200 said:
For now, are there concrete reasons that the explanation is incorrect?

It's tempting to answer that it's incorrect because we already know the correct explanation, and it's something different. Of course, there is always the possibility that our already-known and correct explanation is in fact wrong and there's a better alternative - but such a hypothetical alternative has to make quantitative mathematical predictions at least as good as the current theory, or it's not even on the playing field. Clearly you proposed explanation does not reach that level, whereas general relativity has survived a century of relentless and skeptical scrutiny.

You've already received one warning today for posting personal and speculative theories. That's not what Physics forums is for.
 
  • #5
Nugatory said:
You've already received one warning today for posting personal and speculative theories. That's not what Physics forums is for.

Thank you. I suppose physics is better served by a forum that discourages independent thought in its students.
 
  • #6
Sturk200 said:
Thank you. I suppose physics is better served by a forum that discourages independent thought in its students.

This policy and the reasons for it are discussed at some length in the FAQ and in the various threads in the Forum feedback section. The very quick summary would be something along the lines of "You can't expand the frontiers of science unless you're already standing at the frontier; PF is here to help people get there".
 
  • Like
Likes Doc Al
  • #7
Nugatory said:
expand the frontiers

I apologize if the impressions given was of somebody trying to expand the frontiers, as that is not the intention underlying it. The question posed is simple and avowedly naive. Why can't the resistance to a spring force be explained by the gravitational force set up between the mass to which the force is being applied and the spring mechanism. I assume there is some quite simple demonstration of why this cannot be the case, or else Einstein never would have written a more complicated theory.
 
  • #8
Maybe I can try to clarify the question because I feel like there must be some obvious error in my thinking.

Here is the phenomenon: So imagine we have a spring mounted to a pretty large bowling ball and we take this rig to space. We attach a test mass to the end of this spring rig, compress the spring, and let go. We observe that the test mass is propelled forward with some acceleration. (The bowling ball is included to emphasize the gravitational force of interest, though we could just as well remove the bowling ball and consider the force between the test mass and the spring itself).

How do we analyze this situation? According to the mechanics that I've learned -- assuming I understand it correctly -- the acceleration with which our test mass is propelled will be a function of three things: (1) the force due to the spring (f=-kx), (2) the inertial mass (-kx=ma), and (3) the gravitational force due to the interaction between the bowling ball and the test mass (f=Gmm/r^2, where the two m's refer to the masses of the bowling ball and the test object). The total description of this test object will then be -kx - Gm1m2/r2 = m1a. That is to say, the spring force (which will push in the positive x direction) minus the force due to the gravitational attraction between the two masses (which will pull back in the negative x direction) will be proportional to the conjoined mass and acceleration of the object.

Now here is where my imagination begins to falter. Suppose we try the same experiment again, keeping everything constant, except that we use a more massive test object. The obvious result will be that the more massive object will be propelled with a lower acceleration. I know that the equations tell us that the lower acceleration will be a consequence of two things: the increased gravitational force between the test object and the bowling ball, and the increased inertial mass itself. But I can't see how these two things can be experimentally distinguished from one another, since the two are linked by definition. All we see in the phenomenon is that acceleration decreases in proportion to changes in the mass of the test object. What prevents us from saying that this relationship is entirely due to the gravitational attraction between the mass and the bowling ball, since that measurement already accounts for the inertial mass?
 
  • #9
The thread is reopened, with the reminder that the goal of PF is to learn about existing theories, not invent new ones.
 
  • #10
Sturk200 said:
The total description of this test object will then be -kx - Gm1m2/r2 = m1a.
...

Suppose we try the same experiment again, keeping everything constant, except that we use a more massive test object. ... All we see in the phenomenon is that acceleration decreases in proportion to changes in the mass of the test object. What prevents us from saying that this relationship is entirely due to the gravitational attraction between the mass and the bowling ball
Look at the equation you posted:
-kx - Gm1m2/r2 = m1a
Or solving for a
a=-kx/m1 - Gm2/r2

Clearly, the acceleration does not "decrease in proportion to" m1, the relationship is more complicated than proportionality. Also, the gravitational term in the equation does not change at all as a function of m1. So gravitation has the wrong form to account for an acceleration which varies as a function of m1.

The algebra simply doesn't support your idea here.
 
  • #11
Thanks for reopening the thread.

DaleSpam said:
Clearly, the acceleration does not "decrease in proportion to" m1

This is right as long as we consider the gravitational and inertial effects to be two distinct things. What I was trying to ask is why we don't simply say that the inertial resistance to acceleration is entirely a consequence of the gravitational attraction between the test object and the "bowling ball," since that gravitational attraction increases in direct proportion to the inertial mass. Mathematically, this idea might be expressed by replacing the inertial m1 with the gravitational term, and allowing the latter to speak for both, giving something like:
-kx = Gm1m2/r2 ⋅ a.

Of course this equation is an absolute mess, since the maneuver throws off all the units and constants. But what struck and mystified me was that -- and please correct me if I'm wrong here -- it seems to capture the proportionality between the mass of the test object and the inertial resistance to acceleration, and if the proportionality is captured, then the rest of the work is just in fixing the units and constants. Then the thought is, if the inertial effect can be captured entirely by talking about gravitational attraction, then why speak of inertial mass at all?

I think I see now why this wouldn't work, or at least one reason why it wouldn't. The new equation lends a symmetry to the situation that is not present in the phenomenon itself. For if we make the test of increasing the mass of the bowling ball, the equation predicts that this will have an effect on the acceleration of the test mass in equal proportion as would an increased mass of the test mass itself, which is contrary to fact. In fact increasing the mass of the bowling ball would have barely any effect, while increasing that of the test object would have a larger, more noticeable effect. The equation, then, does not allow us to scale the relative importance of the two masses for determining acceleration, and this relative importance is essential.

I hope this counts as understanding existing concepts.
 
  • #12
Sturk200 said:
and please correct me if I'm wrong here -- it seems to capture the proportionality between the mass of the test object and the inertial resistance to acceleration
Yes, this is wrong. Even in your mangled form it is still not a proportionality. It seems very apparent to me, do you not see that directly by looking at the equation (either the incorrect one you wrote or the correct one I wrote)? Neither one is a proportionality.

As you say, the effect of changing the other mass would not be captured correctly either.
 
Last edited:
  • #13
DaleSpam said:
Yes, this is wrong. Even in your mangled form it is still not a proportionality. It seems very apparent to me, do you not see that directly by looking at the equation (either the incorrect one you wrote or the correct one I wrote)? Neither one is a proportionality.

As you say, the effect of changing the other mass would not be captured correctly either.

Maybe I'm not getting the meaning of proportionality clear. In my mangled equation, if you increase m1, and hold all else constant, acceleration must decrease proportionally. That means acceleration is proportional to the inverse of the mass, no?
 
  • #14
Sturk200 said:
Why can't the resistance to a spring force be explained by the gravitational force set up between the mass to which the force is being applied and the spring mechanism. I assume there is some quite simple demonstration of why this cannot be the case
Sturk200 said:
What prevents us from saying that this relationship is entirely due to the gravitational attraction between the mass and the bowling ball, since that measurement already accounts for the inertial mass?
Put the bowling ball in a sling behind the mechanism so that the acceleration due to gravity between the ball and the mechanism is positive. Compare with acceleration when the ball was on top of it.

Or use two identical setups with same propelling force, but different masses of the mechanism.
 
  • #15
Sturk200 said:
Maybe I'm not getting the meaning of proportionality clear. In my mangled equation, if you increase m1, and hold all else constant, acceleration must decrease proportionally. That means acceleration is proportional to the inverse of the mass, no?
Proportionality means the following: given X and Y are proportional, when you multiply X by A, you end up with Y multiplied by A.
In the equation:
##a=kx/m_1 - Gm_2/r_2## (the original had a wrong sign by kx - the 0 point is the neutral position for a top-loaded spring, so for negative gravity you have positive spring force, or vice versa)
when you increase m1 by e.g. a factor of 2, you don't get twice as large nor an inverse proportionality (i.e. 1/2), nor any other such simple relationship.

Your equation (which needs to be said again: is bad algebra) has the same problem.

In concrete terms, the equation above is such, that there exists a mass m1 for which the acceleration changes sign from positive to negative (ball is too heavy to be launched against gravity). In a proportional relationship where everything else is constant, you'd need a negative mass to get that result.
 
  • #16
Sturk200 said:
Maybe I'm not getting the meaning of proportionality clear. In my mangled equation, if you increase m1, and hold all else constant, acceleration must decrease proportionally. That means acceleration is proportional to the inverse of the mass, no?
Ah, my apologies I misread your formula (the multiplication dot looked like a minus sign on my mobile device). Your formula is indeed a proportionality.

As such it is experimentally wrong for any scenario where both the spring and gravitational forces are important. In other words, experiments show that the relationship is not proportional, so your mangled equation cannot be fit to the data.

I don't think it is appropriate to continue discussing a known wrong equation. Let's stick to correct ones. You can ask questions about how we can experimentally determine the correct equation without requiring discussion of the incorrect one.
 
Last edited:
  • #17
DaleSpam said:
As such it is experimentally wrong for any scenario where both the spring and gravitational forces are important. In other words, experiments show that the relationship is not proportional, so your mangled equation cannot be fit to the data.

Summary: Experiments show that the relationship between inertial mass and acceleration is proportional. Experiments also show that the relationship between inertial mass and the gravitational force is proportional. Bad idea: Woah, maybe inertial mass is just due to the gravitational force! Definitive objection to bad idea: But experiments show that the relationship between the gravitational force and acceleration is not proportional when gravitation is not the only relevant force.
 
  • #19
Thanks for all the help.
 

What is the difference between inertial and gravitational mass?

Inertial mass is a measure of an object's resistance to acceleration when a force is applied, while gravitational mass is a measure of an object's gravitational attraction to other objects. They are fundamentally different concepts, but they happen to be equal in value according to the principle of equivalence in Einstein's theory of general relativity.

Why is the relationship between inertial and gravitational mass important?

The relationship between these two types of mass is important because it helps us understand the fundamental nature of gravity and its effects on objects in the universe. It also plays a crucial role in the development of theories such as general relativity, which have significant implications for our understanding of the universe.

How is the equality between inertial and gravitational mass confirmed?

The equality between these two types of mass has been confirmed through various experiments, such as Galileo's experiments with falling objects, Newton's laws of motion, and more recently, the precise measurements of the gravitational constant and the acceleration due to gravity on Earth.

What are some real-world applications of the relationship between inertial and gravitational mass?

The relationship between inertial and gravitational mass has many practical applications, including the development of technologies such as satellite navigation systems, space travel, and precision instruments like atomic clocks. It also helps us understand the behavior of objects in the universe, such as the motion of planets and stars.

Is the relationship between inertial and gravitational mass affected by extreme conditions?

While the equality between these two types of mass holds true in most situations, there are some extreme conditions, such as near the speed of light or near a black hole, where the relationship may break down. These scenarios require more complex theories, such as those proposed by Einstein in general relativity, to fully understand the relationship between inertial and gravitational mass.

Similar threads

  • Classical Physics
Replies
6
Views
112
  • Mechanics
Replies
22
Views
2K
Replies
1
Views
2K
Replies
3
Views
919
Replies
117
Views
6K
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
806
Replies
6
Views
726
Replies
38
Views
24K
Back
Top