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Northbysouth
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*The title for this question is incorrect. I messed it up with another question. My apologies.
Replace the system of two forces and one couple shown in Prob. 2/158 by a wrench. Determine the magnitude of the moment M of the wrench, the magnitude of the force R of the wrench, and the coordinates of the point P in the x-y plane through which the wrench passes.
I found the magnitude of the resultant to be:
Rx = -49 kN
Ry = -35*sin(69.04) = -32.684
Rz = 35*cos(69.04)
R = 60.216 kN
I'm fairly sure that this value is correct but I am not sure
Then for the moment I got:
Mx = -35*cos(20.956)*1.8m + 35sin(20.956)(4.7m) = 0
My = 49*1.8m = 88.2 kNm
Mz -36 kNm
M = 95.264 kNm
But it says this answer is wrong.
From this point I am unsure how to find the location of the x and y coordinate
All help would be appreciated
Homework Statement
Replace the system of two forces and one couple shown in Prob. 2/158 by a wrench. Determine the magnitude of the moment M of the wrench, the magnitude of the force R of the wrench, and the coordinates of the point P in the x-y plane through which the wrench passes.
Homework Equations
The Attempt at a Solution
I found the magnitude of the resultant to be:
Rx = -49 kN
Ry = -35*sin(69.04) = -32.684
Rz = 35*cos(69.04)
R = 60.216 kN
I'm fairly sure that this value is correct but I am not sure
Then for the moment I got:
Mx = -35*cos(20.956)*1.8m + 35sin(20.956)(4.7m) = 0
My = 49*1.8m = 88.2 kNm
Mz -36 kNm
M = 95.264 kNm
But it says this answer is wrong.
From this point I am unsure how to find the location of the x and y coordinate
All help would be appreciated
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