Rewrite in logarithmic form: e^(-1) = c

In summary, the logarithmic form of e^(-1) is ln(c) = -1, where ln represents the natural logarithm and c is the base of the logarithm. To solve for c, we can take the antilogarithm of both sides, which means raising both sides to the power of e. This gives us c = e^(-1). The exponential form of e^(-1) = c is c = e^(-1). The value of c represents the base of the logarithm, which is being raised to the power of -1 to equal e. The natural logarithm is commonly used in scientific calculations to solve exponential equations, model natural phenomena, and analyze data with nonlinear relationships. It is
  • #1
Vi Nguyen
13
0
Rewrite in logarithmic form:

e^(-1) = c
 
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  • #2
\(\displaystyle \ln\left(e^{-1}\right)=\ln(c)\)

\(\displaystyle -1=\ln(c)\)
 
  • #3
thanks
 
  • #4
You have posted a number of logarithm problems without, apparently, know what a "logarithm" is! If you are not taking a class that involves logarithms, where are you getting these problems?

$y= a^x$ is equivalent to $log_a(y)= x$.
 
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1. What is the logarithmic form of e^(-1) = c?

The logarithmic form of e^(-1) = c is ln(c) = -1.

2. How do you solve for c in the equation e^(-1) = c?

To solve for c, take the natural logarithm of both sides: ln(e^(-1)) = ln(c). This simplifies to ln(c) = -1. Then, use the inverse property of logarithms to rewrite the equation as c = e^(-1).

3. What does the value of c represent in the equation e^(-1) = c?

The value of c represents the result of raising e to the power of -1, which is approximately 0.3679.

4. Can you rewrite the equation e^(-1) = c in exponential form?

Yes, the exponential form of e^(-1) = c is c = e^(-1).

5. What is the significance of e in the equation e^(-1) = c?

The number e, also known as Euler's number, is a mathematical constant that is approximately equal to 2.71828. It is commonly used in logarithmic and exponential functions, and in this equation, it represents the base of the natural logarithm.

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