Rotational Equilibrium (Finding tension)

In summary, the problem involves a restaurant sign hanging from a metal bar attached to a wall and supported by a wire. The bar has a mass of 5 kg, while the sign has a mass of 23 kg and hangs from 2 chains located at .3 m from each end of the bar. The wire makes a 28 degree angle with the bar. The goal is to find the tension of the wire and the normal force exerted by the bar against the building. By drawing a free body diagram and using the equations Fweight = mg and Fnormal = Ftension*sin28, the tension of the wire can be calculated as (5g + 46g)/cos28 and the normal force can be calculated as (5
  • #1
Pinkchika88
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Homework Statement


a restaurant sing hangs from a metal bar attached to a wall and supported by a wire. the bar has a mass of 5 kg, and a length of 1.2 m. the sign has a mass of 23 kg and hangs from 2 chains located at .3 m from each end of the bar. the wire makes a 28 degree angle with the bar


Homework Equations


find the tension of the wire
find the normal force the bar exerts against the building


The Attempt at a Solution


i drew the free body diagram and found that the Fweight of the bar and the Fweight of both chains should equal Ftension*cos28. is this right?
 
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  • #2
Fweight of bar= 5g Fweight of chains= 23g*2 Ftension cos28 = Ftension*cos28 Ftension= (5g + 46g)/cos28 for normal force, i know that it should equal the Ftension*sin28. so Fnormal = Ftension*sin28 = (5g + 46g)*sin28/cos28
 

Related to Rotational Equilibrium (Finding tension)

What is rotational equilibrium?

Rotational equilibrium is a state in which an object is not rotating or is rotating at a constant angular velocity. This means that the net torque acting on the object is equal to zero.

What is the formula for finding tension in a system in rotational equilibrium?

The formula for finding tension in a system in rotational equilibrium is T = rF, where T is the tension force, r is the distance from the pivot point to the point where the force is applied, and F is the force applied.

How do you determine the direction of tension in a system in rotational equilibrium?

The direction of tension in a system in rotational equilibrium is always perpendicular to the line connecting the pivot point and the point where the force is applied. This is known as the "right-hand rule."

What is the significance of rotational equilibrium in real-life applications?

Rotational equilibrium is important in many real-life applications, such as balancing objects on a seesaw or designing structures like bridges and cranes. It helps ensure that the object or structure remains stable and does not tip over.

What factors can affect rotational equilibrium in a system?

The factors that can affect rotational equilibrium in a system include the magnitude and direction of forces applied, the distance from the pivot point to the point where the force is applied, and the mass and distribution of mass of the object.

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