- #1
momoneedsphysicshelp
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- Homework Statement
- A 13.6 kg mass is placed on a vertically hanging spring (k=8.8). The mass is slowly released so it comes to rest. What is the displacement from the natural length of the spring?
- Relevant Equations
- Gravitational potential energy = m*g*x
Elastic potential energy = (1/2)kx^2
Assuming zero spring mass and zero friction,
At the greatest value of x, the loss in gravitational potential energy should equal the loss in elastic potential energy.
so I did
(1/2)kx^2=mgx
to isolate x in the formula,
x=(2mg)/k
then I plugged in my values so:
(2*13.6*9.81)/8.8= 30.3218
so the displacement is 30.32 m.
Can anyone please check what mistake I made in this problem, when I submit it, it is incorrect.
At the greatest value of x, the loss in gravitational potential energy should equal the loss in elastic potential energy.
so I did
(1/2)kx^2=mgx
to isolate x in the formula,
x=(2mg)/k
then I plugged in my values so:
(2*13.6*9.81)/8.8= 30.3218
so the displacement is 30.32 m.
Can anyone please check what mistake I made in this problem, when I submit it, it is incorrect.
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