Simple Wavelength Problem (wire of fixed length vibrating)

[JoeyBob]

Homework Statement

See attached

Relevant Equations

wavelength = 2L/N

When the question says 8 antinodes, doesn't that mean N=8? but when I do 2L/8, I get 0.24.

To get the right answer you do 2LN, but that doesn't make sense to me for I thought the equation was 2L/N??

 

[haruspex]

Homework Statement:: See attached
Relevant Equations:: wavelength = 2L/N

When the question says 8 antinodes, doesn't that mean N=8? but when I do 2L/8, I get 0.24.

To get the right answer you do 2LN, but that doesn't make sense to me for I thought the equation was 2L/N??

Are you saying the official answer is 16 times the length of the wire? Bizarre.

 

[Frabjous]

I think the answer is wrong. There are 2 anti-nodes per wave length. Since you have 8 anti-nodes, there are 4 wavelengths on the wire. Therefore the wavelength is .24m which is what you got if you add units.

 

[JoeyBob]

Are you saying the official answer is 16 times the length of the wire? Bizarre.

Yeah the correct answer is 15.36, I guess its just wrong.

 

[haruspex]

Yeah the correct answer is 15.36, I guess its just wrong.

Safe guess.