Solve Reversible Expansion of Ideal Gas: q, Work, ΔU

In summary, the conversation discusses a problem involving two paths for an ideal gas undergoing reversible expansion. The pressure is constant, while the volume and temperature are not constant. The goal is to calculate q(rev), work(rev), and ΔU. The person attempting the solution initially assumes that Cp (heat capacity at constant pressure) should be used, but the book recommends using Cv (heat capacity at constant volume) instead. They question this because the pressure is constant and the volume changes. They wonder if the book is suggesting that the change in volume is small enough to use Cv. The person requests clarification and assistance.
  • #1
SpringWater
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Homework Statement


The problem provides two paths. P1,V1,T1------->P1,V2,T3 (this is the only one i do not understand) for AN IDEAL GAS reversible expansion

Pressure---constant
Volume---not constant
Temperature---not constant

Calculate the q(rev)=? work(rev)=? and ΔU=?

Homework Equations





The Attempt at a Solution



Because the pressure is constant I assumed that Cp(heat cap@ constant pressure) should be used instead of Cv (heat cap@constant volume)

so...

Work(rev)=∫Cp(T)dT however the book says use ∫Cv(T)dT why is this?

It does not make sense to me because the pressure is constant and the volume changes so why use Cv over Cp Cp=5/2*R Cv=3/2R or is the book stating that the change in volume is so small that we can still use Cv(T).

Any help would be greatly appreciated

Thank you
 
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  • #2
Which book is that?
 

1. What is the definition of reversible expansion of an ideal gas?

The reversible expansion of an ideal gas refers to a process in which the gas expands or contracts without any energy loss or gain. This means that the system is in thermal equilibrium with its surroundings at all times during the expansion or contraction.

2. How is the heat transferred during reversible expansion of an ideal gas?

The heat transfer during reversible expansion of an ideal gas is through the process of conduction, where the gas particles collide with each other and transfer thermal energy. This process is reversible, meaning the heat can be transferred in both directions.

3. What is the equation for calculating work done during reversible expansion of an ideal gas?

The equation for calculating work done during reversible expansion of an ideal gas is given by: W = -PΔV, where W is the work done, P is the pressure, and ΔV is the change in volume of the gas.

4. How does the internal energy of an ideal gas change during reversible expansion?

The internal energy of an ideal gas remains constant during reversible expansion, as there is no change in temperature and no heat is added or removed from the system. This is because the process is reversible and occurs without any energy loss or gain.

5. What is the relationship between heat, work, and change in internal energy during reversible expansion of an ideal gas?

According to the first law of thermodynamics, the change in internal energy (ΔU) of an ideal gas during reversible expansion is equal to the sum of heat (q) and work (W) done on the gas. This can be represented by the equation: ΔU = q + W.

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