Solving a Dilute Barium Hydroxide-H2SO4 Reaction

[iRaid]

Homework Statement

Barium hydroxide is soluble in water. What are the spectator ions in the reaction of a dilute solution of barium hydroxide with hydro-sulfuric acid?

Homework Equations

The Attempt at a Solution

The chemical equation is:
$Ba(OH)_{2(aq)}+H_{2}SO_{4(aq)} \rightarrow BaSO_{4(s)}+2H_{2}O_{(l)}$
In my notes it says sulfates are soluble except for a few, Ba is one of them.
The ionic equation is:
$Ba^{2+}+6O^{2-}+4H^{+}+S^{2-} \rightarrow BaSO_{4(s)}+4H^{+}+2O^{2-}$
Not sure on the ionic equation...
Any help because I thought the spectators are the ones that cancel out?

 

[Borek]

Check your notes on dissociation - how do the bases dissociate? How do the acids dissociate?

 

[iRaid]

There's nothing about that in my notes :\

 

[Borek]

Then check your book or ask prof. Google.

 

[DeeNos]

The spectator ions in this reaction are the ones that do not participate in the actual chemical reaction and remain in their original form. In this case, the spectator ions are the Ba^{2+} and the 4H^{+} ions. They do not combine to form new compounds and are present on both sides of the equation. The Ba^{2+} ions come from the barium hydroxide and the 4H^{+} ions come from the hydro-sulfuric acid. These ions do not react with each other and therefore do not affect the overall reaction.