- #1
Nishikino Maki
- 18
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Homework Statement
A peaked roof is symmetrical and subtends a right angle, as shown. Standing at a height of distance h below the peak, with what initial speed must a ball be thrown so that it just clears the peak and hits the other side of the roof at the same height?
Diagram: http://imgur.com/bi1efMm
Homework Equations
[itex]x=vcos(\theta)t[/itex]
[itex]y=vsin(\theta)t-\frac{1}{2}gt^2[/itex]
[itex]\frac{1}{2}mv^2=mgh[/itex]
The Attempt at a Solution
This is supposed to be a kinematics problem, but I wasn't too sure how to do it that way so I used energy principles. Using the above equation, I got that the velocity should be [itex]\sqrt{2gh}[/itex] by simply rearranging the variables, however, the answer key says that it's [itex]\sqrt{5/2gh}[/itex].