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In order to apply perturbation theory to the ψ[itex]_{200}[/itex] and ψ[itex]_{210}[/itex] states, we have to solve the matrix eigenvalue equation.
Ux=λx where U is the matrix of the matrix elements of H[itex]_{1}[/itex]= eEz between these states.
Please see the matrix in attachment 1.
where <2,0,0|z|2,1,0>=<2,1,0|z|2,0,0>=3a[itex]_{o}[/itex]
Solving this matrix we get, λ[itex]_{1}[/itex]=3ea[itex]_{o}[/itex]|E| and λ[itex]_{2}[/itex]= -3ea[itex]_{o}[/itex]|E|
Then we find eigenvectors to get x[itex]_{1}[/itex] =(1/√2 1/√2)[itex]^{T}[/itex] and x[itex]_{2}[/itex]= (1/√2 -1/√2)[itex]^{T}[/itex]
**** They finally said that ψ[itex]_{1}[/itex] = (ψ[itex]_{200}[/itex] + ψ[itex]_{210}[/itex])/√2
and ψ[itex]_{2}[/itex] = (ψ[itex]_{200}[/itex] - ψ[itex]_{210}[/itex])/√2
How did they get this? How did they combine ψ[itex]_{1}[/itex] and ψ[itex]_{2}[/itex] as follows? It is just the linear combination that I don't get. Thank you.
Ux=λx where U is the matrix of the matrix elements of H[itex]_{1}[/itex]= eEz between these states.
Please see the matrix in attachment 1.
where <2,0,0|z|2,1,0>=<2,1,0|z|2,0,0>=3a[itex]_{o}[/itex]
Solving this matrix we get, λ[itex]_{1}[/itex]=3ea[itex]_{o}[/itex]|E| and λ[itex]_{2}[/itex]= -3ea[itex]_{o}[/itex]|E|
Then we find eigenvectors to get x[itex]_{1}[/itex] =(1/√2 1/√2)[itex]^{T}[/itex] and x[itex]_{2}[/itex]= (1/√2 -1/√2)[itex]^{T}[/itex]
**** They finally said that ψ[itex]_{1}[/itex] = (ψ[itex]_{200}[/itex] + ψ[itex]_{210}[/itex])/√2
and ψ[itex]_{2}[/itex] = (ψ[itex]_{200}[/itex] - ψ[itex]_{210}[/itex])/√2
How did they get this? How did they combine ψ[itex]_{1}[/itex] and ψ[itex]_{2}[/itex] as follows? It is just the linear combination that I don't get. Thank you.
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