- #1
stunner5000pt
- 1,461
- 2
Homework Statement
As in the diagram.
Homework Equations
Cosine law
sine law
The Attempt at a Solution
if we do attempt the magnitudes of u and w and the angle between them 60 degrees, I can solve for the opposite side where v is supposed to be.
I calculated
[tex] |k \vec{v}|^2 = |u|^2 + |w|^2 - 2|u||w| \cos 60 [/tex]
when I calculate the above I got the value of the right side as square root 52
[tex] \sqrt{52} = \frac{\sqrt{52}}{7} |\vec{v}| [/tex]
Would this mean that to get w as a linear combination of u and v, we simply can write
[tex] \vec{w} = \vec{u} - \frac{\sqrt{52}}{7} \vec{v} [/tex]
is that correct?
Thanks for your help.