Some questions about sound(sine) waves.

  • Thread starter Thread starter ZooBooBooZoo
  • Start date Start date
  • Tags Tags
    Waves
AI Thread Summary
The discussion focuses on calculating when the function f(x) = sin(x) + sin(1.05x) equals zero to understand the frequency of sound pulses. The relationship Sin(a) + Sin(b) = 2 Cos((a-b)/2) Sin((a+b)/2) is highlighted as a key mathematical tool for this analysis. For a sound wave at 440Hz, the pressure variation over time is expressed as Sin(2*∏*f*t), with ω defined as 2*∏*f. The analysis reveals that the function oscillates at a high frequency due to the Sin(1.025 ω t) term, while the modulation occurs at a lower frequency from the Cos(0.025 ω t) term. Understanding these relationships aids in grasping the behavior of sound waves and their fluctuations.
ZooBooBooZoo
Messages
1
Reaction score
0
Hi all.

I'm a music student and I've been trying to educate myself about acoustics lately.

I'm exploring the correlations between two pure sound waves.
This might be more of a mathemetical question rather than a physics one but anyways:

I want to know how can I calculate when/how freuqently this function:
f(x)=sin(x)+sin(1.05x)
will be zeroed.

I want to know this so I can now know frequent the pulses occur(by pulses I mean the fluctuating volume of the sound).

Also, what is the proper way to define the sine function of , say, 440Hz?
Sin(440) ?

Thx in advance, hope I'm not too noobish :)
 
Physics news on Phys.org
Use the relation Sin(a) + Sin(b) = 2 Cos((a-b)/2) Sin((a+b)/2)

If you have a sound at frequency f = 440Hz, the pressure varies in time (t) like

Sin(2*∏*f* t) = Sin(ω* t)

or

Sin(2*∏*f* t + shift) = Sin(ω* t + shift)

Usually, one defines ω=2*∏*f.

Concerning your signal and the beats, you will get from above:

f(ω t) = Sin(ω t) + Sin(1.05 ω t) = 2 Cos(0.025 ω t) Sin(1.025 ω t)

From this, you can see when the wave f(ω t) goes to zero.
It does that at a high frequency because of the second factor Sin(1.025 ω t).
But the whole high-frequency wave is modulated by the first factor Cos(0.025 ω t) which goes to zero at a lower frequency.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top