Splitting Fractions (Integrals)

FuturEngineer
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Homework Statement


Evaluate

Integrate (2-3x/(Sqrt.(1 - x^2))) dx

Homework Equations


1/Sqrt.(1-x^2) = arctan

The Attempt at a Solution


I am so lost, but this is what I've tried, but didn't work...

I separated the integral into two so
Integral of (2/(Sqrt.(1-x^20))) dx - integral of (3x/(Sqrt.(1-x^2))) dx
I am not sure how to proceed? Help! [/B]
 
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this can be solved using a trig substitution for x. Can you think of what this substitution should be to simplify the denominator?
 
FuturEngineer said:

Homework Statement


Evaluate

Integrate (2-3x/(Sqrt.(1 - x^2))) dx

Homework Equations


1/Sqrt.(1-x^2) = arctan

The Attempt at a Solution


I am so lost, but this is what I've tried, but didn't work...

I separated the integral into two so
Integral of (2/(Sqrt.(1-x^20))) dx - integral of (3x/(Sqrt.(1-x^2))) dx
I am not sure how to proceed? Help! [/B]
Looks like a natural for trig substitutions for both integrals
 
I would NOT use a trig substitution for \frac{3x}{\sqrt{1- x^2}}. Instead let u= 1- x^2
 
HallsofIvy said:
I would NOT use a trig substitution for \frac{3x}{\sqrt{1- x^2}}. Instead let u= 1- x^2
A trig substitution would work, but I agree that an ordinary substitution (as you suggest) would be easier, which makes it a better choice.
 
Thanks!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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