What are the forces involved in lifting a 1450-lb load with a hydraulic crane?

[Feodalherren]

Homework Statement

The hydraulic crane is used to lift the 1450-lb load. Determine the force in the hydraulic cylinder AB and the force in links AC and AD when the load is held in the position shown.

Homework Equations

The Attempt at a Solution

I don't even know...

 

[SteamKing]

Homework Statement

The hydraulic crane is used to lift the 1450-lb load. Determine the force in the hydraulic cylinder AB and the force in links AC and AD when the load is held in the position shown.

Homework Equations

The Attempt at a Solution

I don't even know...

Work back from the load and draw separate free body diagrams for the individual pieces comprising the crane mechanism. By applying the equations of statics to each piece, you should be able to establish te forces in links AC and AD and in the hyd. cyl. AB.

 

[Feodalherren]

So at joints C and D do I let there be a Cx, Cy and Dx, Dy respectively or do I just keep it as Fwd and Fwc? Either way I can't seem to solve it.

∑Fx=0=WD-4293cos19.74

ΣFy=0=Fwc Sin19.74 - 1450

Fwc= 4203 lb
WD = 4041 lb

Then at joint C∑Fx=0=CDsin30 - CAsin30 - 4041
∑Fy=0=1450-CDcos30-CAcos30

CD = 4878
CA = -3204

Incorrect.
Ah my angle was incorrect, substituted 19.74 with 6.18. Still incorrect.

 

[Dr.D]

Take moments about D.

 

[rezeew]

I can provide a response to the above content by analyzing the situation and applying principles of statics. In this scenario, the hydraulic crane is being used to lift a 1450-lb load. To determine the forces involved, we need to consider the equilibrium of forces acting on the crane.

First, let's consider the hydraulic cylinder AB. We can use the equation F = PA, where F is the force, P is the pressure, and A is the area. The pressure in the hydraulic cylinder is constant, so we can assume that the force in AB is equal to the force in the load, which is 1450 lbs.

Next, let's consider the forces in links AC and AD. These links are connected to the hydraulic cylinder at point A, so they will also experience the same force as AB. However, since they are angled, we need to use trigonometry to determine the components of the force acting in the horizontal and vertical directions. Using the equation Fx = Fcosθ and Fy = Fsinθ, where θ is the angle of the link, we can calculate the forces in AC and AD to be 1450cos(60) = 725 lbs and 1450sin(60) = 1258.3 lbs, respectively.

In conclusion, the force in the hydraulic cylinder AB is 1450 lbs, and the forces in links AC and AD are 725 lbs and 1258.3 lbs, respectively. These forces are necessary to maintain the equilibrium of the crane and keep the load in the position shown.