Stellar structure - Helium burning

In summary: V/kgIn summary, the energy generated per unit mass of helium burned when producing equal amounts of carbon and oxygen is 4.319330048 x 10^27 MeV/kg.
  • #1
PaulaS
19
0
1. The problem statement.
Calculate the energy generated per unit mass, if helium burning produces equal amounts (mass fractions) of carbon and oxygen.
mH = 1.672621581 x 10^-27 kg


2. The attempt at a solution
Helium burning produces carbon according to the following reaction:
3He -> C [E(released) = 7.275 MeV]

Helium burning produces oxygen according to the following reactions:
3HE -> C [E(released) = 7.275 MeV]
He + C -> O [E(released) = 7.162 MeV]
______________________________________________ overall reaction for He:
4He -> O [E(released) = 14.437 MeV]


equal mass fractions => X(C) = X(O)
=> m(C)/m(total) = m(O)/m(total)

And then? I have no idea how to continue the exercise. Can anyone provide me with a hint?

Thanks
 
Last edited:
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  • #2
for your question! Let's break down the problem into smaller steps:

1. Determine the mass of carbon and oxygen produced per unit mass of helium burned:
As stated in the problem, the mass of helium (mH) is 1.672621581 x 10^-27 kg. Since the mass fractions of carbon and oxygen are equal, we can assume that the mass of carbon (mC) and oxygen (mO) produced are also equal. Let's represent this mass as mX. Therefore, we can write the following equation:
mC = mO = mX

2. Calculate the energy released per unit mass of helium burned:
From the given reactions, we know that for every 4 units of helium burned, 14.437 MeV of energy is released. Therefore, for 1 unit of helium burned, the energy released would be:
E(released) = (14.437 MeV / 4) = 3.60925 MeV

3. Calculate the energy released per unit mass of carbon and oxygen produced:
Since the mass of carbon and oxygen produced are equal (mC = mO = mX), we can calculate the energy released per unit mass of carbon and oxygen as:
E(released) = 3.60925 MeV / mX

4. Substitute the value of mX from step 1 into the equation from step 3:
E(released) = 3.60925 MeV / mX
= 3.60925 MeV / (mC + mO)
= 3.60925 MeV / (2mX) [since mC = mO = mX]
= 1.804625 MeV / mX

5. Substitute the value of mX into the equation:
mX = mH / 4 [since 4 units of helium is needed to produce 1 unit of carbon and oxygen]
Therefore, mX = (1.672621581 x 10^-27 kg) / 4 = 4.1815539525 x 10^-28 kg

6. Substitute the value of mX into the equation from step 4:
E(released) = 1.804625 MeV / mX
= 1.804625 MeV / (4.1815539525 x 10^-28 kg)
= 4.319330048 x 10^27 Me
 

Related to Stellar structure - Helium burning

1. What is helium burning?

Helium burning is a nuclear fusion process that occurs in the cores of stars with masses between 0.4 and 2.0 times that of the Sun. It is the second stage of nuclear fusion in a star's life, following hydrogen burning.

2. How does helium burning differ from hydrogen burning?

Hydrogen burning fuses four hydrogen nuclei (protons) to form one helium nucleus. Helium burning, on the other hand, fuses three helium nuclei to form one carbon nucleus. This process requires higher temperatures and pressures compared to hydrogen burning.

3. What is the energy source of helium burning?

The main source of energy in helium burning is the conversion of mass into energy through the fusion process. This energy is released in the form of gamma rays and is what keeps a star shining and stable.

4. How does the structure of a star change during helium burning?

During helium burning, the core of a star becomes denser and hotter as more helium nuclei are fused together. This leads to an increase in the rate of nuclear fusion, causing the star to expand and become more luminous.

5. How long does helium burning last in a star's lifetime?

The duration of helium burning depends on the mass of the star. For a star with a mass similar to the Sun, helium burning can last for approximately 100 million years. For more massive stars, it can last for a shorter period of time, while for less massive stars, it can last for billions of years.

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