- #1
kudoushinichi88
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Homework Statement
During a hurricane, winds can whip horizontally at speeds of 150 km/h. Given that
the density of air is 1.20 kg/m3 and the wind after striking the person is brought to
rest, calculate the force of the wind on the person. You may assume the person's
area to be 1.50 m high by 0.50 m wide. Will this person be knocked off his feet if
he is not holding on to any support? State any further assumptions you have made
regarding the person and the ground.
Homework Equations
Density and momentum
The Attempt at a Solution
Here's how I derive the equation for the force. To me, it looked like nonsense, but the units checks out. I am not sure if what I am doing is correct and if it is, I am not sure how to justify it.
Density of air is
[tex]\rho=\frac{M}{V}[/tex]
where M is mass and V is volume. We know that volume is Area x length. In this case, area is the area of the person and the length is speed of the wind v multiplied by the time the wind is hitting the person.
So far we have
[tex]\rho Al=M[/tex];
[tex]\rho Avt=M[/tex]
We know that momentum is Mv, so we multiply v on both sides of the equation. We also know that Force is rate of change of momentum. So if we take the t as dt and divide both sides with that, we get
[tex]\rho Av^2=\frac{Mv}{dt}[/tex]
And finally,
[tex]F=\rho Av^2[/tex]
This gives me a numerical value of 1565N. This force will of course cause the person to be knocked of his feet.
Is it correct to say I am assuming that all the momentum of the wind is transferred to the person?