The unit of measurement of degree of dissociation ( α ) ?

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The discussion centers on the unit of measurement for the degree of dissociation (α) in electrolytic solutions, defined by the formula α = (Kd/C)0.5, where Kd is the dissociation constant and C is the total concentration of the electrolyte. Participants debate the units of Kd and concentration, with some asserting that Kd is unit-less because it represents a ratio of concentrations. However, it is clarified that concentration is measured in mol/L, leading to the conclusion that α is a dimensionless fraction representing the percentage of dissociated solute. The conversation emphasizes the importance of understanding the relationships between these variables to accurately interpret the degree of dissociation in electrolytic systems.
Nader AbdlGhani
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You have to show your attempts, this is a forum policy. Also, all homework like questions should go to homework forum.
What's the unit used to measure α ? if α=(Kd/C)0.5 where Kd is the dissociation constant and C is the total concentration of electrolyte .
 
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Nader AbdlGhani said:
What's the unit used to measure α ? if α=(Kd/C)0.5 where Kd is the dissociation constant and C is the total concentration of electrolyte .

perhaps ..degree of dissociation refers to the
amount of solute dissociated into ions or radicals per mole. its denoted by alpha.

The classical Theory of electrolytic dissociation,is based on the assumption of the incomplete dissociation of the solute,
characterized by the degree of dissociation α, that is,the fraction of the electrolyte molecules that dissociate.
for details ; see <http://encyclopedia2.thefreedictionary.com/Electrolytic+Dissociation>
 
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Why don't you plug units into the formula and see what you get? What is the unit of the concentration? What is the unit of Kd?
 
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Borek said:
Why don't you plug units into the formula and see what you get? What is the unit of the concentration? What is the unit of Kd?
I've already done that , but before I did so , my teacher had told me it's unit-less , he said that according to our school textbook , according to this idea , concentration is measured in mol/Litre and Kd doesn't have a unit as it's a ratio between two constants , therefore the unit of measuring alpha should be Litre/mol ,which sounds a little bit weird
 
Nader AbdlGhani said:
Kd doesn't have a unit

Sure it does. Please write the formula.

Besides, I just realized your formula for α looks odd.
 
Borek said:
Sure it does. Please write the formula.

Besides, I just realized your formula for α looks odd.
I'm sorry but what formula you want me to write ? and what do you mean the formula for alpha looks odd ? thanks .
 
Write the formula for Kd, to see what are Kd units.

α is just the dissociation percentage (fraction), I don't see how it can be calculated using formula you gave in the opening post.
 
Borek said:
Write the formula for Kd, to see what are Kd units.

α is just the dissociation percentage (fraction), I don't see how it can be calculated using formula you gave in the opening post.
If ##\mathbf{AB \leftrightarrow A^+ + B^-}## then ##\mathbf{K_d=\frac{[A^+][B^-]}{[AB]}}##
then ##\mathbf{K_d=\frac{α^2C}{1-α}}## , and ##\mathbf{1-α\approx1}## therefore ##\mathbf{α=\sqrt{\frac{K_d}{C}}}## where C (concentration) is measured in Mol/litre and ##K_d## is unit-less .
 
I see, that's an approximation only.

Why do you think Kd is unit-less? You wrote a formula - what does it tell you?
 
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