Thermal expansion of a liquid in a cylindrical container

In summary, the conversation discusses the relationship between the coefficient of linear thermal expansion of a liquid and the container it is held in. It is observed that when the container is heated, the level of the liquid remains the same. The relevant equations for the liquid level and volume are given, and it is concluded that the change in volume for both the container and the liquid is the same. The relationship between the new and old volumes of the liquid is then compared and it is determined that the coefficient of linear thermal expansion of the liquid is equal to three times the coefficient of linear thermal expansion of the container.
  • #1
issacnewton
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Homework Statement


There is liquid in a cylindrical container at some level. Now when the container is heated, the level of the liquid remains the same in the container. What is the relationship between the coefficient of linear thermal expansion of liquid and the container ?

Homework Equations


[tex]\Delta V = V_o 3\alpha \Delta T[/tex]
[tex]\Delta l = l_o \alpha \Delta T [/tex]

The Attempt at a Solution



Now as the temperature increases, all dimensions of the container increase. Its height increases and also its radius increases. Since liquid remains at the same level, does that mean that the change in volume for both of them is the same ? Please guide... If we mark the level of the liquid before heating by some marker, then the liquid remains at this marker position even after the heating.

Thanks
 
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  • #2
What is the relevant equation for the liquid level h (as a function of V) ?
 
  • #3
I think I found the answer... Let original radius of cylinder be r and original liquid marker position be x. Then the original volume of the liquid is
[tex] \pi r^2 x[/tex]
Let new radius of the container be [itex]r'[/itex] and new liquid marker position be [itex]x'[/itex]. Let [itex]\alpha_c[/itex] be the coefficient of the linear thermal expansion of the container and let [itex]\Delta T[/itex] be the change in temperature.. Then we have
[tex]r' = r [ 1 + \alpha_c \Delta T] [/tex]
[tex]x' = x [ 1 + \alpha_c \Delta T][/tex]

Now the new volume of the liquid is [itex]\pi r'^2 x' [/itex]. Which is equal to
[tex]\pi r^2 [ 1 + \alpha_c(\Delta T)]^2 x [ 1 + \alpha_c(\Delta T)] [/tex]
[tex] \pi r^2 x [ 1 + \alpha_c(\Delta T)]^3 [/tex]

So we have
[tex]\frac{V^{liquid}_{new}}{V^{liquid}_{old}} = [ 1 + \alpha_c(\Delta T)]^3 [/tex]

But the new volume of liquid is related to old volume of liquid by the relation involving the coefficient of volume thermal expansion of the liquid.

[tex]V^{liquid}_{new} = V^{liquid}_{old} [ 1 + \beta_{liq} (\Delta T)] [/tex]

Comparing two equations, we get

[tex] 1 + \beta_{liq} (\Delta T) = [ 1 + \alpha_c(\Delta T)]^3 [/tex]

Since [itex]\alpha_c[/itex] is very small for most of the materials, we can drop higher order terms here.

[tex] 1 + \beta_{liq} (\Delta T) \approx 1 + 3 \alpha_c(\Delta T) [/tex]

Would this be correct ?
 

What is thermal expansion?

Thermal expansion is the tendency of matter to change in shape, area, and volume in response to a change in temperature.

How does thermal expansion affect liquids in a cylindrical container?

In a cylindrical container, thermal expansion causes the liquid to expand in volume as the temperature increases, which can result in an increase in pressure within the container.

What is the coefficient of thermal expansion?

The coefficient of thermal expansion is a measure of how much a material expands or contracts when subjected to a change in temperature. It is usually expressed in units of length per degree Celsius (or Fahrenheit).

What factors can affect the thermal expansion of a liquid in a cylindrical container?

The thermal expansion of a liquid in a cylindrical container can be affected by the type of liquid, the material and thickness of the container, the temperature change, and the amount of liquid in the container.

How can the thermal expansion of a liquid in a cylindrical container be calculated?

The thermal expansion of a liquid in a cylindrical container can be calculated using the formula: ΔV = V0 * α * ΔT, where ΔV is the change in volume, V0 is the initial volume, α is the coefficient of thermal expansion, and ΔT is the change in temperature.

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