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FlyingSpartan
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Homework Statement
A well lagged calorimeter of mass 120g contains 200g of water and 50g of ice, initial at 0°C. A jet of steam is blown through the water until the water temperature reaches 30°C.
Calculate the mass of steam that must condensed.
The specific heat capacity of Copper: 380Jkg-1K-1
The specific heat capacity of Water: 4200Jkg-1K-1
The specific heat capacity of Ice: 2100Jkg-1K-1
The specific latent heat of fusion of Ice: 3.25x105 Jkg-1
The specific latent heat of vaporization of Water: 2.25x106Jkg-1
Homework Equations
Q=mcΔθ
Q=ml
The Attempt at a Solution
My attempt was using Q=mcΔθ, for water (200x-3) x (4200) x (30) = 25200Jkg-1K-1
And similar for Ice
(50x10-3)x(2100)x(30)=3150Jkg-1K-1
However to me it doesn't look like I'm going anywhere.. any help will be appreciated.