- #1
Silverhobbiest
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Homework Statement
In a frictionless piston-cylinder system, there are 3 kg of R-134a initially at 280 kPa and 15 °C. Heat is transferred to the system in the amount 120 kJ. What will the final temperature of the refrigerant be (deg C)?
Homework Equations
Q - W = ΔU (internal energy)
Q - Wb (boundary work) = ΔH (enthalpy)
(if pressure is constant) Wb = P(v2-v1)
[where v is specific volume]
The Attempt at a Solution
I assumed that pressure was constant for this problem because the piston is implied to be free to move. Also, I know that there is boundary work because if the piston is free to move then the volume is changing.
So, I used the equation:
Q - Wb = ΔH
I identified the refrigerant to be in the superheated vapor phase and used the property tables to calculate the specific volume to the refrigerant at the initial state and got 0.078215 m3/kg and calculated the enthalpy to be 264.12kJ/kg.
I was then stuck on how to find boundary work because I have no idea how to find v2 with the given information. I planned on calculating boundary work so that I can use the equation to solve for h2 and then use the property tables to locate the temperature of the substance.
I became frustrated and attempted to ignore it entirely and got an incorrect answer of 59.4 degrees Celcius.
How do I find boundary work? Is my approach correct? Please help me solve thi problem so that I can understand what I'm doing wrong.