Thermodynamics resistance temperature scale

AI Thread Summary
The discussion addresses an error in a homework statement regarding the temperature scale used in a resistance equation, clarifying that α and β should be in Celsius rather than Kelvin. The equation R=Ro(1 +αt+βt2) is examined, with confusion arising about isolating temperature t in relation to the resistance scale. Participants emphasize that the constants α and β are defined in Celsius^-1 and Celsius^-2 to align with the corrected temperature scale. The conversation highlights the need to understand the distinction between the resistance value and the temperature equivalent on the ideal gas scale. Overall, the clarification aids in grasping the relationship between resistance and temperature in thermodynamics.
jeremyskate
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Homework Statement


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IMPORTANT:There is an error in the statement.α and β are in C not K

2. Homework Equations
R=Ro(1 +αt+βt2)

The Attempt at a Solution


I really don't know what to do because if I isolate t in the equation it will give me the temperature on the ideal gas scale whereas the temperature I need to find is on the resistance scale.
 
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Re-read the problem statement: where is "K" used? What does the "correction" imply should be used instead?
 
The temperature is in celsius degrees not kelvin so the constant α is in celcius^-1 and β in celcius^-2 in order to negate t and t^2. This is a correction our teacher made after giving us the statement. Is that what you were reffering to?
 
Yes.
 
Are you saying I simply need to solve R for the given conditions? Because that would give me a value of resistance not temperature and the exersice is to find the ideal gas temperature equivalent on the resistance scale.
 

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