- #1
Someone_physics
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Background
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Consider the following thought experiment in the setting of relativistic quantum mechanics (not QFT). I have a particle in superposition of the position basis:
[tex] H | \psi \rangle = E | \psi \rangle [/tex]
Now I suddenly turn on an interaction potential [itex] H_{int} [/itex] localized at [itex] r_o = (x_o,y_o,z_o) [/itex] at time [itex]t_o[/itex]:
$$
H_{int}(r) =
\begin{cases}
k & r \leq r_r' \\
0 & r > r'
\end{cases}
$$
where [itex]r[/itex] is the radial coordinate and [itex]r'[/itex] is the radius of the interaction of the potential with origin [itex] (x_o,y_o,z_o) [/itex]. By the logic of the sudden approximation out state has not had enough time to react. Thus the increase in average energy is:
[tex] \langle \Delta E \rangle = 4 \pi k \int_0^{r'} |\psi(r,\theta,\phi)|^2 d r [/tex]
(assuming radial symmetry).
Now, let's say while the potential is turned on at [itex] t_0[/itex] I also perform a measurement of energy at time [itex] t_1 [/itex] outside a region of space with a measuring apparatus at some other region [itex] (x_1,y_1,z_1)[/itex]. Using some geometry it can be shown I choose [itex] t_1 > t_0 + r'/c [/itex] such that:
[tex] c^2(t_1 - t_0 - r'/c)^2 -(x_1 - x_0)^2 - (y_1 - y_0)^2 - (z_1 - z_0)^2 < 0 [/tex]
Hence, they are space-like separated. This means I could have one observer who first sees me turn on the potential [itex] H_{int} [/itex] and measure a bump in energy [itex] \langle \Delta E \rangle [/itex] but I could also have an observer who sees me first measure energy and then turn on the interaction potential.
Obviously the second observer will observe something different.
Question
---
How does relativistic quantum mechanics deal with this paradox?
---
Consider the following thought experiment in the setting of relativistic quantum mechanics (not QFT). I have a particle in superposition of the position basis:
[tex] H | \psi \rangle = E | \psi \rangle [/tex]
Now I suddenly turn on an interaction potential [itex] H_{int} [/itex] localized at [itex] r_o = (x_o,y_o,z_o) [/itex] at time [itex]t_o[/itex]:
$$
H_{int}(r) =
\begin{cases}
k & r \leq r_r' \\
0 & r > r'
\end{cases}
$$
where [itex]r[/itex] is the radial coordinate and [itex]r'[/itex] is the radius of the interaction of the potential with origin [itex] (x_o,y_o,z_o) [/itex]. By the logic of the sudden approximation out state has not had enough time to react. Thus the increase in average energy is:
[tex] \langle \Delta E \rangle = 4 \pi k \int_0^{r'} |\psi(r,\theta,\phi)|^2 d r [/tex]
(assuming radial symmetry).
Now, let's say while the potential is turned on at [itex] t_0[/itex] I also perform a measurement of energy at time [itex] t_1 [/itex] outside a region of space with a measuring apparatus at some other region [itex] (x_1,y_1,z_1)[/itex]. Using some geometry it can be shown I choose [itex] t_1 > t_0 + r'/c [/itex] such that:
[tex] c^2(t_1 - t_0 - r'/c)^2 -(x_1 - x_0)^2 - (y_1 - y_0)^2 - (z_1 - z_0)^2 < 0 [/tex]
Hence, they are space-like separated. This means I could have one observer who first sees me turn on the potential [itex] H_{int} [/itex] and measure a bump in energy [itex] \langle \Delta E \rangle [/itex] but I could also have an observer who sees me first measure energy and then turn on the interaction potential.
Obviously the second observer will observe something different.
Question
---
How does relativistic quantum mechanics deal with this paradox?
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