Time period of a harmonic oscillator

In summary, the given equation represents a system that is not a harmonic oscillator, except for when n=2. The period of this system can be obtained by finding the value of n that satisfies the equation ##\frac {d^2 x }{dt^2} + \omega^2 x = 0## and calculating the period using ##\omega##.
  • #1
VVS2000
150
17
Homework Statement
Given is the potential energy of the harmonic oscillator: U=a|x|^n, amplititude is A
Find the time period of this harmonic oscillator
Relevant Equations
E=(1/2)m(dx/dt)^2 + a|x|^n
20200918_164850.jpg
 
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  • #2
Your result is written as
[tex]4A\sqrt{\frac{m}{2E}}\int_0^1 \frac{dx}{\sqrt{1-x^n}}[/tex]
where amplitude A is
[tex]A=(\frac{E}{a})^{\frac{1}{n}}[/tex]
 
  • #3
anuttarasammyak said:
Your result is written as
[tex]4A\sqrt{\frac{m}{2E}}\int_0^1 \frac{dx}{\sqrt{1-x^n}}[/tex]
where amplitude A is
[tex]A=(\frac{E}{a})^{\frac{1}{n}}[/tex]
No, I have'nt written 4A. It's 4. A is inside the root in the denominator.
But how do you solve that integral?
 
  • #4
anuttarasammyak said:
Your result is written as
[tex]4A\sqrt{\frac{m}{2E}}\int_0^1 \frac{dx}{\sqrt{1-x^n}}[/tex]
where amplitude A is
[tex]A=(\frac{E}{a})^{\frac{1}{n}}[/tex]
No, I have'nt written 4A. It's 4. A is inside the root in the denominator.
But how do you solve that integral?
 
  • #5
I made a replacement of x/A ##\rightarrow## x.

The definite integral is a function of ##\Gamma## functions of ##\frac{1}{n}##.
 
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  • #6
Harmonic oscillator in classical physics are not systems subject to an force/ente proportional to its "displacement"? So n shouldn't be two?
Or it is not a harmonic oscillator?
 
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  • #7
As noted by LCSphysicist (#6), this is NOT a harmonic oscillator (except when n=2). The word 'harmonic' is specifically used twice. Is there a possibility this is a 'trick' question?

A harmonic oscillator is one which has a restoring given by:
##\vec F = -k\vec x ##
If I were answering I would demonstrate that only n=2 gives a harmonic oscillator. (Hint, what is the relationship between ##\vec F ## and U?)

Then express in the usual SHM equation format:
##\frac {d^2 x }{dt^2} + \omega^2 x = 0##
You then get the period from ##\omega##.

Just a thought.
 

What is a harmonic oscillator?

A harmonic oscillator is a physical system that follows a repeating pattern of motion, where the restoring force is proportional to the displacement from the equilibrium position. Examples of harmonic oscillators include a mass attached to a spring, a pendulum, and an LC circuit.

What is the time period of a harmonic oscillator?

The time period of a harmonic oscillator is the time it takes for the system to complete one full cycle of motion. It is denoted by the symbol T and is measured in seconds.

How is the time period of a harmonic oscillator calculated?

The time period of a harmonic oscillator can be calculated using the equation T = 2π√(m/k), where m is the mass of the object and k is the spring constant. This equation assumes that there is no damping or external forces acting on the system.

What factors affect the time period of a harmonic oscillator?

The time period of a harmonic oscillator is affected by the mass of the object, the spring constant, and the initial displacement from the equilibrium position. It is also affected by any external forces or damping present in the system.

Why is the time period of a harmonic oscillator important?

The time period of a harmonic oscillator is important because it is a fundamental property of the system that helps us understand and predict its behavior. It is also used in various applications, such as in the design of oscillating systems and in measuring physical quantities like frequency and energy.

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