- #1
fog37
- 1,568
- 108
Torque Free Rotation...again...
Hello Forum,
I have read an old, but good, thread about torque free rotation:
https://www.physicsforums.com/showthread.php?t=405781
I am still unclear on how, from the inertial (lab) frame of reference, the moment of inertia I, which is a tensor with 9 components, changes with time t...
A rigid body moving in the air changes its coordinates relative to the origin of a fixed lab frame of reference. Why would the moment of inertia change too?
Torque free means zero net torque acting on the rigid body. But torque is a quantity that depends on the choice of the pole about which torque is calculate: from the lab frame, the choice of different poles will lead to different numerical values for the torque, correct?
It is possible to diagonalize the moment of inertia and find the 3 principal directions. If the moment of inertia has components that are not constants but instead depend on position (x,y,z), we will find a different triad of principal axes for each different point P since there is a different inertia tensor for each different point P, correct?
thanks,
fog73
Hello Forum,
I have read an old, but good, thread about torque free rotation:
https://www.physicsforums.com/showthread.php?t=405781
I am still unclear on how, from the inertial (lab) frame of reference, the moment of inertia I, which is a tensor with 9 components, changes with time t...
A rigid body moving in the air changes its coordinates relative to the origin of a fixed lab frame of reference. Why would the moment of inertia change too?
Torque free means zero net torque acting on the rigid body. But torque is a quantity that depends on the choice of the pole about which torque is calculate: from the lab frame, the choice of different poles will lead to different numerical values for the torque, correct?
It is possible to diagonalize the moment of inertia and find the 3 principal directions. If the moment of inertia has components that are not constants but instead depend on position (x,y,z), we will find a different triad of principal axes for each different point P since there is a different inertia tensor for each different point P, correct?
thanks,
fog73