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freutel
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Homework Statement
A train wagon of mass M moves on a rail with constant velocity V (without friction). It passes a sand hopper which pours sand in the wagon at constant rate C [kg/s]. The sand falls vertically so it does not transfer any horizontal momentum to the wagon. The length of the wagon is L [m].
Question 1: Determine the velocity of the train wagon as a function of time V(t) while it is under the sand hopper.
Question 2: Show that the total time T that it takes for the wagon to fully pass the hopper machine is T=M/C*(exp(CL/MV)-1)
Homework Equations
- Conservation of momentum MwagonV0=(Mwagon+msand)*V1
- F=ma=dP/dt (Newton's second law)
- t=msand/C
- Straight-line motion equations
x=x0+v0xt+½axt2 (Equation 2)
vx2=v0x2+2a(x-x0) (Equation 3)
x-x0=½(v0x+vx)t (Equation 4)
The Attempt at a Solution
The first question was pretty easy. Because I need the answer from question 1 to solve question 2 I want to make sure that I have the right answer for question 1.
Question 1:
Using conservation of momentum I got MwagonV0=(Mwagon+msand)*V1 and the mass of the sand can be written as Ct. Subbing that in you get MwagonV0=(Mwagon+Ct)*Vt. This gives an equation for Vt -> Vt=Mwagon*V0/(Ct+Mwagon)
Question 2:
This one is tricky and it definitely needs integrating if you look at the equation. I have a feeling there are multiple ways to approach this but every approach I did ended up in chaotic equations that did not help. First I used Newton's second law --> F=dP/dt
Pt=Mtvt with the mass being dependent of time because of Mwagon+Ct
dP/dt=Mtdv/dt+vtdm/dt (dm/dt is the change in mass per unit time which is C)
F=Mtdv/dt+Cvt
When isolating dV/dt and integrating that I got
V=(F-CV)ln(M2+C2T2)
M2+C2T2=exp(V/(F-CV)
This is definitely going in the wrong direction and I got no L in the equations.
Then I started with equation 2 with x being L --> L=V0t+½at2.
Acceleration is dV/dt which is CMV/((Ct+M)2) but subbing this in gives again nothing I can work with.
Then I used equation 3 which resulted in
(MV)2/((M+Ct)2)=V02+2(dV/dt)*L
Isolating dV/dt gives
-C2t2V2/(2(M2L+C2T2L)=dV/dt
This is also a pain to integrate but I used an integration calculator and I ended up with an arctan in my equation.
This is going nowhere and I would really appreciate some help.