- #1
iqjump123
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Hello all.
I am in the process of designing a circuit that involves a resistor divider that connects to a buffer to be connected to a DAQ system. This circuit is being made because the input voltage coming in will be in the range of tens of volts, and what I want is a smaller Vpp wave.
Attached is a pdf of the circuit I built and the simulation results.
When I physically build the circuit, I get the correct voltage but without the positive half of the voltage- so it looks like the positive half of the voltage is cut off. It seems that it has to do with the voltage rails, but I checked my circuit to make sure and even replaced the battery pair with new ones, with no avail.
I am using an LT1010 buffer chip, and the voltage divider ratio was 1/4, down to a quarter.
Since this response when I built it didn't make sense, I simulated the circuit using spice orcad. The second picture in the pdf shows the results. As you can see, the divider voltage is virtually none, and the output isn't even showing anything. I presume adding a load resistor on the output of the buffer will show something, but nonetheless, the output from the resistor divider should show a tuned down voltage of 1.25Vpp sin wave (since vin was 5vpp) , and without a DC offset.
My guess is that it has something to do with how I position my virtual ground from the dual supply and the supply of all the other devices, but I am lost at this point.
Thanks in advance!
iqjump123
I am in the process of designing a circuit that involves a resistor divider that connects to a buffer to be connected to a DAQ system. This circuit is being made because the input voltage coming in will be in the range of tens of volts, and what I want is a smaller Vpp wave.
Attached is a pdf of the circuit I built and the simulation results.
When I physically build the circuit, I get the correct voltage but without the positive half of the voltage- so it looks like the positive half of the voltage is cut off. It seems that it has to do with the voltage rails, but I checked my circuit to make sure and even replaced the battery pair with new ones, with no avail.
I am using an LT1010 buffer chip, and the voltage divider ratio was 1/4, down to a quarter.
Since this response when I built it didn't make sense, I simulated the circuit using spice orcad. The second picture in the pdf shows the results. As you can see, the divider voltage is virtually none, and the output isn't even showing anything. I presume adding a load resistor on the output of the buffer will show something, but nonetheless, the output from the resistor divider should show a tuned down voltage of 1.25Vpp sin wave (since vin was 5vpp) , and without a DC offset.
My guess is that it has something to do with how I position my virtual ground from the dual supply and the supply of all the other devices, but I am lost at this point.
Thanks in advance!
iqjump123